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Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper I covers physical and inorganic chemistry.

Indian Forest Service (Mains), Chemistry optional · 2016 · Paper I

Q7(a)(ii). Structure of Fe₂(CO)₉ and the 18-electron rule

Question

Write the structure of Fe₂(CO)₉. Show that each iron atom in the structure conforms to the 18e rule.

Answer in brief

Two Fe(CO)₃ units linked by three bridging CO ligands and an Fe–Fe bond (D₃ₕ). Each Fe: 8 (Fe) + 6 (three terminal CO) + 3 (three μ₂-CO, one electron to each Fe) + 1 (Fe–Fe bond) = 18 electrons.

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