Q4(b). Chemical potential versus temperature
(i) Show that the slope of μ versus T curve for a pure substance (existing in three phases—solid, liquid and gas) is always negative and is equal to −Sₘ. (ii) Draw a schematic diagram and show that (∂μₛ/∂T)P > (∂μₗ/∂T)P ≫ (∂μ_g/∂T)P. Locate the melting point and boiling point. (5+5 marks)
Answer in brief
At fixed pressure, dμ/dT = −Sₘ. Gas has the most negative slope. The stable phase follows the lowest chemical-potential curve, switching at the melting and boiling intersections.
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Coverschemical potentialμ versus T diagramphase stabilitymelting pointboiling pointmolar entropy
All parts of Question 4
- 4(a) Translational entropy of nitrogen10 marks
- 4(b) Chemical potential versus temperature10 marks
- 4(c) Cell voltage under load and electrolysis10 marks
- 4(d) Selective electrodes and ionic activity10 marks