Indian Forest Service (Mains), Chemistry optional · 2021 · Paper II
Q1(f). Phenol to a reduced aryl ether
Question
Supply reagents and mechanisms for phenol → ethoxybenzene → 1-ethoxycyclohexa-1,4-diene.
Answer in brief
Use base followed by ethyl bromide for ether formation, then Na or Li in liquid NH₃ with an alcohol proton source for Birch reduction.
Key points
- Deprotonate phenol to phenoxide; its oxygen attacks ethyl bromide by SN2, displacing bromide and giving PhOEt.
- A solvated electron adds to the aromatic ring, giving a radical anion; protonation, a second electron transfer and a second protonation reduce two ring positions.
- The electron-donating OEt substituent remains on an unsaturated carbon in the major Birch product, 1-ethoxycyclohexa-1,4-diene.
- The product contains isolated double bonds; ordinary catalytic hydrogenation would not selectively produce this 1,4-diene.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

CoversWilliamson ether synthesisBirch reductionNa in liquid NH₃phenetole1-ethoxycyclohexa-1,4-diene
All parts of Question 1
- 1(a) Aromaticity classifications5 marks
- 1(b) Photochemical hydrogen migration in a diene5 marks
- 1(c) Isotope-labelled acetate pyrolysis5 marks
- 1(d) Kinetic enolate aldol sequence5 marks
- 1(e) Natural rubber and polyethylene5 marks
- 1(f) Phenol to a reduced aryl ether5 marks
- 1(g) Photochemical cleavage and alkene isomerization5 marks
- 1(h) Hyperfine lines of an isotopic radical5 marks