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Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper II covers organic chemistry and spectroscopy.

Indian Forest Service (Mains), Chemistry optional · 2021 · Paper II

Q1(f). Phenol to a reduced aryl ether

Question

Supply reagents and mechanisms for phenol → ethoxybenzene → 1-ethoxycyclohexa-1,4-diene.

Answer in brief

Use base followed by ethyl bromide for ether formation, then Na or Li in liquid NH₃ with an alcohol proton source for Birch reduction.

Key points

  • Deprotonate phenol to phenoxide; its oxygen attacks ethyl bromide by SN2, displacing bromide and giving PhOEt.
  • A solvated electron adds to the aromatic ring, giving a radical anion; protonation, a second electron transfer and a second protonation reduce two ring positions.
  • The electron-donating OEt substituent remains on an unsaturated carbon in the major Birch product, 1-ethoxycyclohexa-1,4-diene.
  • The product contains isolated double bonds; ordinary catalytic hydrogenation would not selectively produce this 1,4-diene.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(f), 2021 Paper II: solution pages 7 and 8
Solution pages 7 and 8 of 40

CoversWilliamson ether synthesisBirch reductionNa in liquid NH₃phenetole1-ethoxycyclohexa-1,4-diene