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Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper II covers organic chemistry and spectroscopy.

Indian Forest Service (Mains), Chemistry optional · 2024 · Paper II

Q1(f). Pulegone to a ring-contracted ester

Question

Identify A and B from pulegone with Br₂/ether, followed by NaOMe/MeOH, and give the mechanism.

Answer in brief

A is the vicinal dibromide across the exocyclic double bond. B is methyl pulegenate, methyl 5-methyl-2-(propan-2-ylidene)cyclopentane-1-carboxylate, as cis/trans ester epimers.

Key points

  • Bromine adds across the exocyclic C=C: one Br is on the ring α-carbon and the other on the external CMe₂ carbon.
  • Methoxide removes an α-H on the other side of the ketone. Intramolecular displacement of the ring-bound Br produces a cyclopropanone intermediate.
  • Methoxide adds to the cyclopropanone carbonyl. Ring opening with elimination of the remaining Br regenerates an exocyclic isopropylidene group.
  • The former ketone carbon becomes the ester carbonyl, outside a five-membered ring. This is the characteristic Favorskii ring contraction.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(f), 2024 Paper II: solution pages 7 and 8
Solution pages 7 and 8 of 34

CoversFavorskii rearrangementpulegonemethyl pulegenatecyclopropanone intermediatering contraction