VKC ScienceChemistry for written exams Telegram

Indian Forest Service (Mains)

Chemistry optional

  • 2 papers
  • 200 marks each
  • 3 h per paper

Paper II covers organic chemistry and spectroscopy.

Indian Forest Service (Mains), Chemistry optional · 2025 · Paper II

Q1(g). Two thermal electrocyclic steps

Question

Identify A at 140 °C and B at 220 °C from the fused cyclobutene/cyclooctene shown. [structure of the bicyclic cyclobutene given in the paper]

Answer in brief

A is cis,cis,trans-cyclodeca-1,3,5-triene; B is trans-bicyclo[4.4.0]deca-2,4-diene.

Key points

  • At 140 °C the strained cyclobutene opens by a thermal 4π conrotatory process, breaking the shared fusion bond to form a conjugated diene.
  • The original cyclooctene C=C lies next to one end of that diene, so the ten-membered ring contains three conjugated double bonds.
  • At 220 °C the six-π triene segment undergoes thermal disrotatory electrocyclisation, giving a fused six/six skeleton.
  • Conrotatory opening generates one trans double bond; the cis,cis,trans triene then closes disrotatorily to the trans-fused bicyclic diene.

The full model answer

As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Model answer to Q1(g), 2025 Paper II: solution pages 7 and 8
Solution pages 7 and 8 of 30

Coverselectrocyclic reactionWoodward–Hoffmann rulesconrotatory ring openingdisrotatory 6π closurecyclobutene ring opening