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VKC Notes · Spectroscopy · Civil Services P-II · IFoS P-II · Geo-Scientist P-III

13.4 Mass Spectrometry: Molecular Ion, Base Peak, Metastable Peak and McLafferty Rearrangement

★★★ 2021–2025: 26 parts, 166 marks (Civil Services 8 parts / 65 m · IFoS 8 / 55 m · Geo-Scientist 10 / 46 m). The McLafferty rearrangement alone is behind a third of them; two isomers told apart by one fragment is the usual form.

Syllabus lines. Civil Services: mass spectrometry: “parent peak, base peak, metastable peak, McLafferty rearrangement”. IFoS: “parent peak, base peak, daughter peak, metastable peak, fragmentation of simple organic molecules; α-cleavage, McLafferty rearrangement”. Geo-Scientist: mass spectrometry, “isotope abundances; the molecular ion, metastable ions. McLafferty rearrangement”.

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CSE 2024 Q7(a) = asked there; tap to open the solved answerSN = line kept in the short notes

13.4.1 How a mass spectrum forms ★★

In electron impact (EI) a 70 eV electron knocks one electron out of the molecule: the molecular ion M⁺•, a radical cation. It carries far more energy than any bond needs, so part of it breaks into fragments. Only charged species are accelerated, sorted by m/z and detected; neutral radicals and molecules are lost unseen.SN

(13.4.1)
(13.4.2)
ion sourcee−, 70 eVaccelerate, Vmagnetic field B(into page)detectorlight ions bend moreheavy: lessM + e− → M+• + 2e−zeV = ½mv2r = mv/zeBm/z = B2r2e / 2Vscan B (or V): each m/zin turn reaches the slit
Fig. 13.4.1 Magnetic-sector instrument: source, accelerating plates, magnet, detector.
Draw it in 60 s: a box (source, 70 eV), two plates (V), a quarter-circle path through a shaded magnet, a detector at the end; write m/z = B2r2e/2V beside it.
  • Molecular (parent) peak: M⁺•, gives the molecular mass. Base peak: the tallest peak, set to 100 %; the most stable ion, often a fragment. Fragment (daughter) ions: everything else. Metastable peak: broad, weak, at a non-integral m/z (13.4.4).SN
102030405060708090050100base peak 43, CH3CO+ (α-cleavage)M+• 86M − 15McLafferty 58m* 37.6 (broad)m/z (relative intensity; pentan-2-one, schematic)%
Fig. 13.4.2 The terms on one spectrum (pentan-2-one, schematic).
Draw it in 60 s: an m/z axis with tall red line at 43 (base), M at 86, McLafferty at 58, M − 15 at 71 and a small hump at 37.6 for m*.

13.4.2 The molecular ion ★★

  • Nitrogen rule: an odd molecular mass means an odd number of N atoms. Fragments: an even-electron ion containing no N has odd m/z (43, 57, 91, 105); an odd-electron ion with no N has even m/z (58, 60, 74, 92, 120): an even fragment from an odd-electron parent with no N signals a rearrangement, not a simple cleavage.SN
  • Where ionisation starts: the electron is removed from the orbital of lowest ionisation energy, n(N) < n(O) ≈ π < σ. In doxepin the N lone pair ionises first CSE 2023 Q8(a)(i) 10m.
  • How strong M⁺• is: aromatics, conjugated alkenes, cyclic compounds strong; ketones, amines, esters medium; branched alkanes and alcohols weak or absent (alcohols show M − 18 instead).
  • When M⁺• is missing, a peak 15 (CH₃), 18 (H₂O), 29 (C₂H₅ or CHO), 31 (OCH₃) or 45 (OC₂H₅) units above the highest peak is the clue.

13.4.3 Isotope peaks ★★

M+2Cl3 : 1M+2Br1 : 1M+2+4Cl29 : 6 : 1M+2+4Br21 : 2 : 1M+2+4ClBr3 : 4 : 1peaks two mass units apart; (a + b)n for n halogen atoms
Fig. 13.4.3 Halogen clusters. Expand (a + b)ⁿ with a, b the isotope fractions.
Draw it in 60 s: five small bar groups: Cl 3:1, Br 1:1, Cl2 9:6:1, Br2 1:2:1, ClBr 3:4:1; write M, +2, +4 under the bars.
  • ³⁵Cl : ³⁷Cl ≈ 3 : 1, ⁷⁹Br : ⁸¹Br ≈ 1 : 1, so one Cl gives M : M+2 ≈ 3 : 1, one Br ≈ 1 : 1, one Cl + one Br ≈ 3 : 4 : 1, from (3 + x)(1 + x) = 3 + 4x + x² IFoS 2024 Q5(g) 5m.SN
  • M+1 from carbon: ¹³C is 1.1 %, so I(M+1)/I(M) ≈ 1.1 % × number of C. A 6.6 % M+1 means about six carbons. S (³⁴S, 4.4 %) also gives a small M+2.SN

13.4.4 Metastable peaks ★★

An ion m₁⁺ that decomposes to m₂⁺ after leaving the source but before the magnet is recorded neither at m₁ nor at m₂ but at a broad, weak peak m*. It proves that m₂ forms from m₁ in one step.

(13.4.3)
  • Doxepin, M⁺• 279 → CH₂=N⁺(CH₃)₂ 58: m* = 58²/279 = 12.06 CSE 2023 Q8(a)(i).SN
  • Peaks 106, P, 65, 46.42, 29, 15: 46.42 is the metastable, so P = 65²/46.42 = 91.0; the step 91 → 65 is loss of C₂H₂ (26) from tropylium IFoS 2023 Q5(g) 5m.SN

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