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7.2 Solutions: Raoult’s and Henry’s Laws, Non-ideal Solutions, Colligative Properties, van ’t Hoff Factor and Activity

★★★ 2021–2026: 42 Geo-Scientist Prelims questions, six to nine every year, the largest single Prelims block in physical chemistry; and 1 IFoS Mains part (10 marks) on activity coefficients. Mains asks the same ideas inside phase equilibria (7.1) and electrochemistry (8.3).

Syllabus lines. Civil Services and IFoS (Phase equilibria and solutions): “phase equilibria in binary systems, partially miscible liquids …; partial molar quantities, their significance and determination; excess thermodynamic functions and their determination”. Geo-Scientist Prelims asks Raoult’s and Henry’s laws, colligative properties and the van ’t Hoff factor every year; Mains Paper II has activity and activity coefficients.

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CSE 2024 Q7(a) = asked there; tap to open the solved answerSN = line kept in the short notes

7.2.1 Raoult’s law and ideal solutions ★★★

(7.2.1)
  • Ideal solution: every component obeys Raoult’s law at all compositions; A–B interactions equal the average of A–A and B–B, so ΔmixH = 0 and ΔmixV = 0 (benzene–toluene, hexane–heptane). In terms of chemical potential, μA = μA* + RT ln xA (6.2).SN
  • Total pressure is linear in the liquid composition Geo Pre 2022 Q65, while 1/p is linear in the vapour composition Geo Pre 2021 Q68. The vapour is richer in the more volatile component: pure pressures 1 : 6 and xA : xB = 1 : 4 give yB = 24/25 = 0.96 Geo Pre 2023 Q61.SN
  • 1 mol benzene (6.0 kPa) + 2 mol toluene (4.8 kPa): p = (1/3)(6.0) + (2/3)(4.8) = 5.2 kPa; ybenzene = 2.0/5.2 = 0.385, not 1/3 Geo Pre 2026 Q64.SN
0.00.20.40.60.81.002468101214mole fraction of benzene: xA  (liquid), yA  (vapour)p / kPaxA  = 0.50: p = 8.25 kPayA  = 0.77pA * = 12.7pB * = 3.8pA  = xA  pA * (dashed)pB  = xB  pB *liquid line: straightvapour curve: 1/p linear in yA 
Fig. 7.2.1 An ideal pair at 25 °C (benzene 12.7, toluene 3.8 kPa, computed): straight liquid line, vapour curve below; at xA = 0.50, yA = 0.77.
Draw it in 60 s: two dashed lines from zero to pA* and pB*, a straight line joining pB* to pA* (sum), a sagging curve under it (vapour); a tie-line from x to y.

7.2.2 Henry’s law and the solubility of gases ★★★

(7.2.2)
  • For a dilute solute the partial pressure is proportional to its mole fraction, but the constant KB is not pB*: a solute molecule is surrounded by solvent, not by its own kind. An ideal-dilute solution: solvent obeys Raoult, solute obeys Henry. Labels for a vapour-pressure plot: the straight line from the origin to K is Henry, the straight line to p* is Raoult, the curve is the real solution Geo Pre 2026 Q65.SN
  • Units follow the composition scale: Pa with mole fraction Geo Pre 2026 Q69. Large K means low solubility. H₂ in water, K = 7.03 × 10⁹ Pa, p = 1.00 × 10⁶ Pa: x = 1.42 × 10⁻⁴ Geo Pre 2021 Q69. O₂, K = 8.0 × 10⁴ kPa kg mol⁻¹, p = 20 kPa: b = 2.5 × 10⁻⁴ mol kg⁻¹ ≈ 0.25 mmol dm⁻³ Geo Pre 2024 Q65. Acetone in chloroform, K = 20 kPa, x = 0.30: p = 6.0 kPa Geo Pre 2025 Q70.SN
  • Ratio of dissolved O₂ and N₂ from air (y = 0.2 and 0.8) with K = 880 and 440: (pO₂/KO₂)/(pN₂/KN₂) = (0.2/880)/(0.8/440) = 0.125 Geo Pre 2022 Q68.
  • K depends on the gas, the solvent and the temperature; CO₂ (reacts with water) is far more soluble than O₂, and O₂ more than N₂ Geo Pre 2024 Q64 Geo Pre 2023 Q66. Gases that liquefy easily (strong attractions) or ionise in water are more soluble; solubility of most gases falls on heating (dissolution is exothermic) Geo Pre 2022 Q69.SN

7.2.3 Non-ideal solutions: positive and negative deviations ★★

  • Positive deviation (A–B weaker than A–A and B–B): molecules escape more easily, p above Raoult, ΔmixH > 0, ΔmixV > 0. Ethanol–water, acetone–CS₂, ethanol–cyclohexane. A large deviation gives a pressure maximum: a minimum-boiling azeotrope (ethanol–water, 95.6% ethanol by mass).SN
  • Negative deviation (A–B stronger, often a new H-bond): p below Raoult, ΔmixH < 0, volume contracts. Acetone–chloroform (C–H···O), HNO₃–water, HCl–water; a pressure minimum gives a maximum-boiling azeotrope. Distillation of azeotropes and partially miscible pairs: 7.1.7.SN
  • In either case each component approaches Raoult as x → 1 and Henry as x → 0; the Duhem–Margules equation links the two partial pressures (6.2.4), so if one component deviates positively the other must too.
01xA p(a) positive deviationp maximum: min-boiling azeotropepB pA 01xA p(b) negative deviationp minimum: max-boiling azeotropepB pA dashed grey: Raoult (ideal) · dotted green: Henry tangent at xA  → 0
Fig. 7.2.2 Positive and negative deviations (computed from a regular-solution model, ξ = ±1.4): total pressure through a maximum or a minimum.
Draw it in 60 s: two boxes: dashed straight Raoult lines; in one the three curves bow upward with a peak in the top curve, in the other they sag with a dip.

7.2.4 Thermodynamics of mixing and excess functions ★★

(7.2.3)
  • Ideal mixing is driven only by entropy (ΔmixH = 0, ΔmixV = 0); ΔmixG < 0 at all compositions, most negative at x = 0.5.SN
  • Excess functions: XE = ΔmixX(real) − ΔmixX(ideal). Determination: GE from vapour pressures (γi = pi/xipi*), HE from calorimetry (heat of mixing), VE from densities (dilatometry), SE = (HE − GE)/T.SN
  • Regular solution: HE = ξnRTxAxB with SE = 0, so ln γA = ξxB². For ξ > 2, ΔmixG has two minima and the liquids separate into two phases: the origin of partial miscibility and of the upper critical solution temperature (7.1.7).SN
0.00.20.40.60.81.00.250.00-0.25-0.50-0.75xA Δmix G / nRTξ = 0ξ = 1.5ξ = 2ξ = 2.5ξ = 3ξ > 2: two minima → two liquid phases (7.1)ξ = 0: ideal, Δmix H = 0
Fig. 7.2.3 Gibbs energy of mixing of a regular solution (computed) for ξ = 0 to 3.
Draw it in 60 s: a deep U for ξ = 0; flatter curves as ξ grows; for ξ = 3 a W with two dips (two liquid phases).

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