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VKC Prelims Notes · Combined Geo-Scientist Prelims · Paper II Chemistry · Unit 9 (C9)

Basic Organic Chemistry: Resonance, Electronic Effects, Aromaticity and Reactive Intermediates

6 questions a year on average (36 in 2021–2026), at the start of the organic block (about Q81–Q90). Almost all are “arrange in order” or “which is most stable” questions drawn as structures.

Syllabus (Paper II, unit 9): Delocalized bonding, resonance, hyperconjugation, inductive and mesomeric effects, hybridization, aromaticity, acidity and basicity of organic compounds, reactive intermediates: carbocations, carbanions, free radicals, carbenes.

9.1Delocalised bonding and resonance

When a π bond, a lone pair, an empty p orbital or an unpaired electron sits next to another π system, the p orbitals overlap side by side and the electrons spread over three or more atoms. This is delocalisation. A single Lewis structure cannot show it, so we draw several resonance structures (contributors) that differ only in the position of π electrons and lone pairs; the real molecule is one resonance hybrid, lower in energy than any contributor. The extra stability is the resonance energy.

Rules for drawing contributors

  • Only electrons move; nuclei stay where they are. Every contributor has the same number of paired and unpaired electrons.
  • Only atoms in one plane with parallel p orbitals can share electrons. A group twisted out of the plane loses its resonance.
  • Second-row atoms cannot exceed an octet.

Which contributor counts most

  1. Complete octets on every atom beat everything else. CH₂=O⁺–CH₃ (all octets) outweighs ⁺CH₂–O–CH₃ (carbon with a sextet).
  2. Fewer formal charges (more covalent bonds) is better; charge separation costs energy.
  3. A negative charge on the more electronegative atom (and positive on the less) is better: in an enolate the form with O⁻ dominates.
  4. Like charges far apart; opposite charges close together.
  5. Equivalent contributors (carboxylate, benzene, allyl) give the largest resonance energy.

Evidence: heats of hydrogenation

Adding H₂ to a C=C releases heat. The more stable the alkene or diene, the less heat it gives out.

  • Cyclohexene: about 120 kJ mol⁻¹. Benzene, if it had three isolated C=C, would release about 360; it actually releases about 208. The difference, about 150 kJ mol⁻¹ (36 kcal), is the resonance energy of benzene.
  • Conjugated dienes release less than isolated dienes (1,3-pentadiene ≈ 226 against 1,4-pentadiene ≈ 254 kJ mol⁻¹).
  • More alkyl groups on the C=C lower the heat (hyperconjugation, 9.2): tetrasubstituted < trisubstituted < disubstituted < monosubstituted; trans < cis.
  • A cyclic monoene takes one H₂; a diene takes two, so its value is roughly double. Compare per C=C only when the number of C=C is the same.

Steric inhibition of resonance

Resonance needs coplanarity. Bulky ortho groups twist –NMe₂, –NO₂ or –COOH out of the ring plane and cut off its resonance with the ring. So 2,6-disubstituted N,N-dimethylanilines are more basic than expected (the lone pair is no longer delocalised), and plain PhNMe₂ is the most resonance-stabilised of the series.

π molecular orbitals of conjugated systems

ψ1 (0 nodes)↑↓ψ2 (1 node) HOMO↑↓ψ3 (2 nodes) LUMOψ4 (3 nodes)C1C2C3C44 π electrons
Fig. 9.1 π molecular orbitals of 1,3-butadiene. Shaded and open lobes are opposite phases.
  • n p orbitals give n π MOs. ψk has k − 1 nodes; energy rises with the number of nodes.
  • Butadiene (4 π e⁻): ψ₁ and ψ₂ are filled. HOMO = ψ₂ (one node, between C2 and C3; C1, C2 in one phase and C3, C4 in the other). LUMO = ψ₃ (two nodes).
  • Allyl system: ψ₁ (bonding), ψ₂ (non-bonding, node through the central carbon), ψ₃ (antibonding). The allyl cation, radical and anion put 2, 3 and 4 electrons into these, so the charge or odd electron sits on C1 and C3 only.

9.2Hyperconjugation

A C–H (or C–C) σ bond on the carbon next to an empty p orbital, a π bond or a radical centre can overlap sideways with it and share its electrons. This is hyperconjugation (σ–π conjugation, or “no-bond resonance”, because the contributors show H⁺ with no bond to carbon).

  • Number of hyperconjugative structures = number of α-C–H bonds, that is, H atoms on carbons directly attached to the cationic, radical or sp² carbon. H on the charged carbon itself does not count, nor do H further away. (CH₃)₃C⁺ has 9; (CH₃)₂CH⁺ has 6; CH₃CH₂⁺ has 3; CH₃–C⁺H–C(CH₃)₃ has only 3, because the quaternary carbon carries no H.
  • It explains: stability of carbocations and radicals 3° > 2° > 1° > methyl; greater stability of more substituted alkenes; the slightly shorter C–C single bond next to a C=C (propene 1.50 Å); the small dipole moment of propene; and the Baker–Nathan order (CH₃ > CH₃CH₂ > (CH₃)₂CH > (CH₃)₃C) seen in some reactions, opposite to the inductive order.
  • σ(C–H) → σ*(C–X) donation (the same idea with an empty σ* orbital) gives the gauche effect in 1,2-difluoroethane (see Unit 10).

9.3Inductive and mesomeric effects

Inductive effect (I)

A permanent polarisation passed along σ bonds by an electronegative or electropositive group. It falls off quickly with distance (almost nil after three bonds).

  • −I (withdraw): –NO₂ > –N⁺R₃ > –CN > –COOH > –F > –Cl > –Br > –I > –OCH₃ > –OH > –C₆H₅.
  • +I (donate): –O⁻ > –COO⁻ > –C(CH₃)₃ > –CH(CH₃)₂ > –CH₂CH₃ > –CH₃.

Mesomeric (resonance) effect (M or R)

Transfer of π or lone-pair electrons through a conjugated system. It acts only at conjugated positions (ortho and para in a benzene ring) but over long distances, and it usually outweighs the inductive effect.

  • +M (lone pair next to the π system): –O⁻ > –NH₂ > –NR₂ > –OH > –OR > –NHCOR > halogens.
  • −M (π bond to an electronegative atom): –NO₂ > –CN > –CHO > –COR > –COOH > –COOR.
  • Halogens are −I and +M; −I wins for reactivity, but +M decides ortho/para orientation.
  • Hammett σp sums up both effects at the para position: –NO₂ 0.78, –CN 0.66, –COCH₃ 0.50, –Cl 0.23, –H 0, –CH₃ −0.17, –OCH₃ −0.27, –OH −0.37, –NH₂ −0.66. Positive = withdrawing.

Dipole moments and molecular polarity

  • Bond dipoles are vectors. For two dipoles μ₁ and μ₂ at angle θ: . 1 D = 3.336 × 10⁻³⁰ C m.
  • One polar bond always makes a molecule polar. Two or more polar bonds may cancel in a symmetric shape (CO₂, BF₃, CCl₄, trans-1,2-dichloroethene, p-dichlorobenzene: zero). A molecule with only non-polar bonds is non-polar.
  • Dichlorobenzenes: ortho (60°) ≈ 2.5 D > meta (120°) ≈ 1.5 D > para = 0. Chlorobenzene ≈ 1.6–1.7 D. In p-BrC₆H₄Cl two nearly equal dipoles almost cancel (≈ 0.1–0.2 D).
  • Where a +M group and a −M group sit para to each other (p-nitroaniline), the dipoles add and the moment is large.

Prelims notes

Read all 10 sections of this unit, the practice questions and every PYQ

Prelims notes open with VKC Basic (₹999 for 6 months) or with the Geo-Scientist Prelims GS + Chemistry test series. They are for reading online; there is no PDF.

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