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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2016 · Paper I

Q6(a)(ii). Labile complexes; lability and d-electron configuration

  • 10 marks
  • Answered
Question

What are “labile” complexes? Outline the relationship between lability and electronic structure of a complex. Name the type of method used in the study of such complexes.

Answer in brief

Labile complexes exchange their ligands rapidly: in Taube's definition, substitution with a half-life under about one minute. Octahedral complexes with electrons in e_g or with fewer than three d electrons are labile; d³ and low-spin d⁴–d⁶ are inert. They are studied by fast-reaction methods (stopped-flow, relaxation, NMR line broadening).

Key points

  • terms of kinetic stability. A complex that undergoes substitution quickly is labile; one that reacts slowly is inert. Thermodynamic stability is a different matter: [Co(NH₃)₆]³+ is thermodynamically unstable in acid yet inert,…
  • small, highly charged ions hold their ligands longer. Water exchange is about 10⁵ s⁻¹ for Mg²+ and about 10⁸ s⁻¹ for the larger Ca²+.
  • labile: all complexes with electrons in the antibonding e_g* orbitals (high-spin Co²+ t_(2g)⁵e_g², high-spin Fe³+ t_(2g)³e_g², Cu²+; Ni²+, d⁸, is labile but slower) and all with fewer than three d electrons (Ti³+, d¹). Inert:…
  • in a dissociative path the octahedron becomes a five-coordinate square pyramid. The change in CFSE is the ligand-field activation energy (LFAE, panel): it is large and positive for d³, d⁸ (+2.00 Dq) and low-spin d⁶ (+4.00 Dq),…

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

  1. Labile and inert: terms of kinetic stability. A complex that undergoes substitution quickly is labile; one that reacts slowly is inert. Thermodynamic stability is a different matter: [Co(NH₃)₆]³+ is thermodynamically unstable in acid yet inert, and keeps for years in solution.
  2. Size and charge: small, highly charged ions hold their ligands longer. Water exchange is about 10⁵ s⁻¹ for Mg²+ and about 10⁸ s⁻¹ for the larger Ca²+.
  3. Electronic structure (Taube): labile: all complexes with electrons in the antibonding e_g* orbitals (high-spin Co²+ t_(2g)⁵e_g², high-spin Fe³+ t_(2g)³e_g², Cu²+; Ni²+, d⁸, is labile but slower) and all with fewer than three d electrons (Ti³+, d¹). Inert: d³ (Cr³+, t_(2g)³) and low-spin d⁴, d⁵, d⁶ (Co³+, t_(2g)⁶).
  4. Why: in a dissociative path the octahedron becomes a five-coordinate square pyramid. The change in CFSE is the ligand-field activation energy (LFAE, panel): it is large and positive for d³, d⁸ (+2.00 Dq) and low-spin d⁶ (+4.00 Dq), which raises the barrier (inert); zero or negative for d⁰–d², high-spin d⁴–d⁷, d⁹, d¹⁰ (labile).
  5. The leaving group matters too: for [Co(NH₃)₅X]ⁿ⁺ + water, k=5.8×10⁻¹² s⁻¹ for X = NH₃ (t_(1/2) 3800 years) but 1.0×10⁻² s⁻¹ for X = ClO₄⁻ (t_(1/2) 7 s).

Methods: labile complexes react within seconds to nanoseconds, too fast for ordinary mixing. They are studied by fast-reaction techniques: stopped-flow (milliseconds), relaxation methods such as temperature jump and pressure jump (microseconds), and NMR line broadening, e.g. ¹⁷O NMR of water exchange. Inert complexes are followed by conventional methods and isotopic labelling (¹⁸O).

Application. inert Co(III) and Cr(III) complexes could be isolated as isomers and so built Werner's coordination theory; the inertness of Pt(II)–N bonds is why cisplatin survives long enough in the body to reach DNA.

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Model answer to Q6(a)(ii), 2016 Paper I: solution page 32
Solution page 32 of 46