Q8(a)(ii). Crystal field theory; [CoF₆]³- versus [Co(NH₃)₆]³+
Explain crystal field theory. How does it differ from valence bond theory? How does this theory account for the fact that [CoF₆]³- is paramagnetic while [Co(NH₃)₆]³+ is diamagnetic though both are octahedral.
Answer in brief
CFT treats ligands as point charges that split the d orbitals (t_(2g) below, e_g above in Oₕ). In both complexes Co(III) is d⁶: with weak-field F⁻, Δₒ<P and the ion is high spin t_(2g)⁴e_g² (4 unpaired, paramagnetic); with NH₃, Δₒ>P and it is low spin t_(2g)⁶ (diamagnetic).
Key points
- the metal–ligand bond is purely electrostatic; ligands are point charges (or point dipoles). In the isolated ion the five d orbitals are degenerate.
- d_(x²-y²) and d_(z²) point at the ligands and are raised (e_g, +0.6Δₒ); d_(xy), d_(xz), d_(yz) point between them and are lowered (t_(2g), -0.4Δₒ). The barycentre is unchanged. Tetrahedral: the order is reversed and Δₜ≈49Δₒ.
- if Δₒ<P (pairing energy) electrons go to e_g unpaired (high spin); if Δₒ>P they pair in t_(2g) (low spin). Δₒ follows the spectrochemical series: I⁻ < Br⁻ < Cl⁻ < F⁻ < H₂O < NH₃ < en < CN⁻ < CO.
- CFSE =(-0.4n_t_(2g)+0.6n_(e_g))Δₒ (+ pairing energies) explains colour (d–d transitions of energy Δₒ), magnetism, hydration-enthalpy trends and Jahn–Teller distortions.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Oₕt_(2g) -0.4Δₒ, e_g +0.6ΔₒSPIN STATEΔₒ vs pairing energy Pμₛ4.90 μ_B vs 0
Crystal field theory
- Model: the metal–ligand bond is purely electrostatic; ligands are point charges (or point dipoles). In the isolated ion the five d orbitals are degenerate.
- Octahedral field: d_(x²-y²) and d_(z²) point at the ligands and are raised (e_g, +0.6Δₒ); d_(xy), d_(xz), d_(yz) point between them and are lowered (t_(2g), -0.4Δₒ). The barycentre is unchanged. Tetrahedral: the order is reversed and Δₜ≈49Δₒ.
- Filling for d⁴–d⁷: if Δₒ<P (pairing energy) electrons go to e_g unpaired (high spin); if Δₒ>P they pair in t_(2g) (low spin). Δₒ follows the spectrochemical series: I⁻ < Br⁻ < Cl⁻ < F⁻ < H₂O < NH₃ < en < CN⁻ < CO.
- CFSE =(-0.4n_t_(2g)+0.6n_(e_g))Δₒ (+ pairing energies) explains colour (d–d transitions of energy Δₒ), magnetism, hydration-enthalpy trends and Jahn–Teller distortions.
How CFT differs from VBT
- VBT: covalent bonds from ligand pairs into empty hybrid orbitals of the metal (d²sp³ inner orbital, sp³d² outer orbital). CFT: no hybridisation, no covalency; only the splitting of d levels by the ligand field.
- VBT cannot explain colour or spectra, does not give the magnitude of magnetic moments or their temperature dependence, and cannot predict which complexes are high spin; CFT explains these through Δₒ and P (and gives numbers such as CFSE). Neither model includes π bonding; ligand field (MO) theory does.
[CoF₆]³- and [Co(NH₃)₆]³+
- Both contain Co(III), d⁶, octahedral.
- F⁻ is a weak-field ligand: Δₒ<P. Configuration t_(2g)⁴e_g², 4 unpaired electrons: μₛ=√(4(4+2))= 4.90 μ_B, paramagnetic (measured close to 5 μ_B). CFSE =-0.4Δₒ.
- NH₃ gives a much larger Δₒ (higher in the spectrochemical series, and Co(III) is highly charged): Δₒ>P. Configuration t_(2g)⁶e_g⁰, no unpaired electron: diamagnetic. CFSE =-2.4Δₒ+2P.
- The same metal ion and geometry give different magnetism only because of the size of Δₒ relative to P; in VBT language [CoF₆]³- is an outer-orbital (sp³d²) and [Co(NH₃)₆]³+ an inner-orbital (d²sp³) complex, a label CFT explains.
Application. nearly all Co(III) complexes are low spin and therefore kinetically inert (t_(2g)⁶); [CoF₆]³- and [Co(H₂O)₃F₃] are the exceptions. The inertness is why Werner could isolate and count the isomers of cobalt(III) ammines.
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All parts of Question 8
- 8(a)(i) EAN rule applied to [Fe(CN)₆]⁴- and [Fe(CN)₆]³-10 marks
- 8(a)(ii) Crystal field theory; [CoF₆]³- versus [Co(NH₃)₆]³+15 marks
- 8(b) High oxidation states of early actinides; stable +2 of Am and No10 marks
- 8(c) Phosphazenes: ring and chain types; substitution reactions15 marks