UPSC Civil Services (Mains), Chemistry optional · 2018 · Paper I
Q1(c)(i). ΔᵣG° for the formation of MgO at 0°C
Question
Consider the formation of MgO(s). Assume that Δ H°ᵣ and Δ S°ᵣ are independent of temperature.
[Mg(s) + 1/2 O₂(g) → MgO(s) Δ H°ᵣ=-602 kJ/mol, Δ S°ᵣ=-108 J/K/mol]
(i) Calculate Δ G°ᵣ for the formation of MgO(s) at 0°C. Is this reaction spontaneous or non-spontaneous at 0°C.
Answer in brief
ΔᵣG°=-572.5 kJ mol⁻¹ at 273.15 K: negative, so the formation of MgO is spontaneous at 0°C.
Key points
- T=0°C=273.15 K; Δ S°ᵣ=-108 J K⁻¹ mol⁻¹=-0.108 kJ K⁻¹ mol⁻¹
- TΔ S°=273.15×(-0.108)=-29.5 kJ mol⁻¹
- Δ G°ᵣ=Δ H°ᵣ-TΔ S°ᵣ=-602-(-29.5) ΔᵣG°=-572.5 kJ mol⁻¹
- Δ G°<0: the reaction is spontaneous at 0°C. Magnesium burns in air once ignited; at room temperature only a thin oxide film forms because the reaction is slow (kinetics), not because it is unfavourable.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
- T=0°C=273.15 K; Δ S°ᵣ=-108 J K⁻¹ mol⁻¹=-0.108 kJ K⁻¹ mol⁻¹
- TΔ S°=273.15×(-0.108)=-29.5 kJ mol⁻¹
- Δ G°ᵣ=Δ H°ᵣ-TΔ S°ᵣ=-602-(-29.5) ΔᵣG°=-572.5 kJ mol⁻¹
- Δ G°<0: the reaction is spontaneous at 0°C. Magnesium burns in air once ignited; at room temperature only a thin oxide film forms because the reaction is slow (kinetics), not because it is unfavourable.
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All parts of Question 1
- 1(a) Particle in a box: probability in the centre half10 marks
- 1(b) Δ U for heating one mole of water from 25 to 30°C10 marks
- 1(c)(i) ΔᵣG° for the formation of MgO at 0°C5 marks
- 1(c)(ii) Temperature at which the spontaneity switches5 marks
- 1(d)(i) BeF₂ linear, SF₂ angular5 marks
- 1(d)(ii) P forms PCl₃ and PCl₅; N forms only NCl₃5 marks
- 1(e) Spontaneity of four redox reactions from E°10 marks