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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2018 · Paper I

Q5(b). Langmuir isotherm at very low and very high pressure

  • 10 marks
  • Answered
Question

Explain Langmuir adsorption isotherm (i) when the gas pressure `P' is very small and (ii) when the gas pressure `P' is very high.

Answer in brief

θ=(KP)/(1+KP). (i) At very low P, KP≪1 and θ=KP: coverage proportional to pressure. (ii) At very high P, KP≫1 and θ→1: a complete monolayer, independent of pressure.

Key points

  • Adsorption stops at a monolayer; all sites are equivalent; the chance of adsorption at a site does not depend on whether neighbouring sites are occupied (no interaction between adsorbed molecules); adsorption and desorption…
  • rate of adsorption =kₐP N(1-θ) (gas pressure times vacant sites); rate of desorption =k_dNθ.
  • At equilibrium kₐP(1-θ)=k_dθ. With K=kₐ/k_d: θ=(KP)/(1+KP)
  • In terms of the volume adsorbed, θ=V/V_∞, the linear form is P/V=(P)/(V_∞)+(1)/(KV_∞): a plot of P/V against P is a straight line, slope 1/V_∞.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Assumptions and derivation

  1. Adsorption stops at a monolayer; all sites are equivalent; the chance of adsorption at a site does not depend on whether neighbouring sites are occupied (no interaction between adsorbed molecules); adsorption and desorption are in dynamic equilibrium.
  2. With N sites and fractional coverage θ: rate of adsorption =kₐP N(1-θ) (gas pressure times vacant sites); rate of desorption =k_dNθ.
  3. At equilibrium kₐP(1-θ)=k_dθ. With K=kₐ/k_d: θ=(KP)/(1+KP)
  4. In terms of the volume adsorbed, θ=V/V_∞, the linear form is P/V=(P)/(V_∞)+(1)/(KV_∞): a plot of P/V against P is a straight line, slope 1/V_∞.

(i) Very low pressure

  1. KP≪1, so 1+KP≈1: θ=KP
  2. Coverage rises linearly with pressure (the initial straight part of the isotherm, like Henry's law). Most sites are empty, and each new molecule finds a vacant site.
  3. For a surface-catalysed decomposition, rate =kθ=kKP: first order in the gas (PH₃ on W at low pressure).

(ii) Very high pressure

  1. KP≫1, so 1+KP≈ KP: θ→1
  2. The surface is saturated with a complete monolayer; more pressure adds nothing. The isotherm is flat.
  3. Rate =kθ=k: zero order, independent of pressure (NH₃ on W, PH₃ on W at high pressure).
  4. In between, θ≈ KPⁿ with 0<n<1, which is the Freundlich form.

Application. the Langmuir form gives the kinetics of heterogeneous catalysis (Haber process on iron, hydrogenation on nickel) and, by fitting V_∞, a first estimate of the surface area of an adsorbent.

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Model answer to Q5(b), 2018 Paper I: solution page 31
Solution page 31 of 55