UPSC Civil Services (Mains), Chemistry optional · 2018 · Paper I
Q8(b)(i). Einstein's law of photochemical equivalence
Question
Define and explain Einstein's law of photochemical equivalence.
Answer in brief
Each molecule taking part in a photochemical reaction absorbs one quantum of radiation, hν, in the primary (light-absorbing) step. One mole of reacting molecules therefore absorbs one einstein, N_Ahν=N_Ahc/λ.
Key points
- in the primary process each molecule that reacts is activated by absorbing one photon; one quantum is absorbed per molecule activated.
- the energy absorbed per mole is E=N_Ahν=(N_Ahc)/(λ), called one einstein. At 494 nm this equals the Cl–Cl bond enthalpy (242 kJ mol⁻¹), so light of shorter wavelength can dissociate Cl₂.
- Φ=(number of molecules reacting)/(number of photons absorbed). The law strictly predicts Φ=1 for the primary step.
- Apparent deviations come from secondary (dark) reactions: Φ≫1 for chain reactions (H₂ + Cl₂, 10⁴ to 10⁶); Φ<1 when excited molecules lose energy by fluorescence, collision or recombination (HI decomposition gives Φ=2 because…
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
- Statement (Stark–Einstein law): in the primary process each molecule that reacts is activated by absorbing one photon; one quantum is absorbed per molecule activated.
- Einstein: the energy absorbed per mole is E=N_Ahν=(N_Ahc)/(λ), called one einstein. At 494 nm this equals the Cl–Cl bond enthalpy (242 kJ mol⁻¹), so light of shorter wavelength can dissociate Cl₂.
- Quantum yield: Φ=(number of molecules reacting)/(number of photons absorbed). The law strictly predicts Φ=1 for the primary step.
- Apparent deviations come from secondary (dark) reactions: Φ≫1 for chain reactions (H₂ + Cl₂, 10⁴ to 10⁶); Φ<1 when excited molecules lose energy by fluorescence, collision or recombination (HI decomposition gives Φ=2 because the H atom attacks a second HI).
- The law holds for ordinary light intensities; with lasers two photons can be absorbed together.
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All parts of Question 8
- 8(a)(i) Products of four interhalogen reactions10 marks
- 8(a)(ii) Number of Re–Re bonds in [Re₂Cl₈]²⁻5 marks
- 8(b)(i) Einstein's law of photochemical equivalence5 marks
- 8(b)(ii) The photochemical reaction of hydrogen and chlorine5 marks
- 8(c) Active sites and functions of cytochrome c and cytochrome P-45015 marks
- 8(d) Stereoisomers of [PtCl₂Br₂(NH₃)₂]10 marks