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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2019 · Paper I

Q5(a). Octafluoroxenate(VI): preparation, structure and bonding

  • 10 marks
  • Answered
Question

How would you prepare octafluoroxenate? Describe its structure and bonding.

Answer in brief

XeF₆ takes up fluoride ion: XeF₆ + CsF → CsXeF₇, then 2CsXeF₇ →Cs₂XeF₈ + XeF₆ (or XeF₆ + 2NOF → (NO)₂[XeF₈]). [XeF₈]²- is a square antiprism; its one lone pair on Xe is stereochemically inactive.

Key points

  • XeF₆ is a fluoride-ion acceptor (Lewis acid). With a fluoride source it gives XeF₇⁻ or XeF₈²-, depending on the proportion of F⁻: 3pt] XeF₆ + CsF → Cs[XeF₇] 2Cs→Cs₂⁺ XeF₆ 3pt] Nitrosyl fluoride gives the nitrosonium salt XeF₆…
  • Xe 8 + 8 F (one each) + 2 (charge) = 18 electrons = 9 pairs: 8 bonding pairs and 1 lone pair (Xe oxidation state +6).
  • an approximate square antiprism (two parallel squares of F, one turned 45° to the other, D_(4d)). One square face is slightly larger, so the true symmetry is nearer C₄ᵥ.
  • VSEPR predicts a definite site for the ninth pair, but the antiprism has none. The lone pair is stereochemically inactive: it stays in the spherical Xe 5s orbital, while eight F crowd round Xe. Its small effect may be the…

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

  1. Preparation: XeF₆ is a fluoride-ion acceptor (Lewis acid). With a fluoride source it gives XeF₇⁻ or XeF₈²-, depending on the proportion of F⁻: 3pt] XeF₆ + CsF → Cs[XeF₇] 2Cs→Cs₂⁺ XeF₆ 3pt] Nitrosyl fluoride gives the nitrosonium salt XeF₆ + 2NOF → (NO)₂[XeF₈]. Large cations (Cs⁺, Rb⁺, NO⁺) stabilise the large anion through lattice energy; the solids are stable well above room temperature but are hydrolysed by moisture.
  2. Electron count: Xe 8 + 8 F (one each) + 2 (charge) = 18 electrons = 9 pairs: 8 bonding pairs and 1 lone pair (Xe oxidation state +6).
  3. Observed structure: an approximate square antiprism (two parallel squares of F, one turned 45° to the other, D_(4d)). One square face is slightly larger, so the true symmetry is nearer C₄ᵥ.
  4. The lone pair: VSEPR predicts a definite site for the ninth pair, but the antiprism has none. The lone pair is stereochemically inactive: it stays in the spherical Xe 5s orbital, while eight F crowd round Xe. Its small effect may be the slight enlargement of one face.
  5. Bonding: the Xe–F bonds are electron-rich, multicentre bonds (three-centre four-electron type using Xe 5p and F 2p orbitals) with large ionic character, Xe^(δ+)–F^(δ-); no 5d participation is needed. High coordination is possible because F is small and very electronegative.

Application. xenon fluorides and their anions are clean fluorinating agents (by-product only Xe); XeF₆ is separated from XeF₄ and XeF₂ by forming involatile NaF.XeF₆-type adducts and then heating them.

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Model answer to Q5(a), 2019 Paper I: solution page 22
Solution page 22 of 40