Q4(c)(i). Time of maximum concentration of B in A → B → C
For the sequential reaction A → B → C (rate constants kA and kB), the rate constants are kA = 5 × 10⁶ s⁻¹ and kB = 3 × 10⁶ s⁻¹. Determine the time when the concentration of B is at a maximum.
Answer in brief
tmax = ln(kA/kB)/(kA − kB) = 2.55 × 10⁻⁷ s.
Part of VKC Basic
Read the key points and the full model answer with VKC Basic
VKC Basic (₹999 for 6 months) opens every solved answer, the notes, the handbook and the daily answer archive. Every Mains test series includes it.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.
Coversconsecutive reactionsfirst-order kineticsmaximum concentration of intermediatesteady-state approximationrate constants
All parts of Question 4
- 4(a) Triple point, stable phase and enthalpy of sublimation of a new drug15 marks
- 4(b)(i) Polarography and concentration polarisation15 marks
- 4(b)(ii) Concentration cells; fuel cells as energy converters5 marks
- 4(c)(i) Time of maximum concentration of B in A → B → C10 marks
- 4(c)(ii) Yield of P₁ from three parallel paths5 marks