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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2026 · Paper I

Q4(a). The polarographic wave at a dropping mercury electrode

  • 10 marks
  • Answered
Question

Draw and discuss the polarographic wave obtained in the case of a dropping mercury electrode in polarography.

Answer in brief

Current against the applied potential of the dropping mercury electrode (DME) gives an S-shaped wave: a small residual current, a steep rise from the decomposition potential, and a plateau (limiting current) with small oscillations. The height of the wave, i_d, measures the concentration; its position, E_(1/2), identifies the species.

Key points

  • before any reduction a small current flows, mainly to charge the double layer of each new drop, with a little from traces of impurities. It rises slowly and almost linearly and forms the baseline.
  • here the species starts to be reduced, for example Cd²+ + 2e⁻ + Hg → Cd(Hg). The current rises steeply, and the concentration of the ion at the drop surface, c₀, falls below the bulk value C (concentration polarisation).
  • at more negative potentials c₀=0. Every ion is reduced as soon as it arrives, so the current is set by the rate of diffusion and stops rising with potential: the plateau. iₗ=iᵣ+i_d.
  • given by the Ilkovič equation, i_d=607 n D^(1/2)m^(2/3)t^(1/6)C (mean current in µA; D in cm² s⁻¹, m in mg s⁻¹, t in s, C in mmol L⁻¹); 708 replaces 607 for the maximum current of each drop. For one capillary and one medium…

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Recording: the unstirred solution (about 10⁻³ to 10⁻⁵ M) is electrolysed between the DME, which falls at 20 to 30 drops a minute, and a large reference electrode (mercury pool or SCE). The applied potential is made steadily more negative and the current, only 10⁻⁵ to 10⁻⁶ A, is recorded. The drop is tiny and easily polarised, so the whole change in voltage appears at the drop.

Parts of the wave

  1. Residual current, iᵣ: before any reduction a small current flows, mainly to charge the double layer of each new drop, with a little from traces of impurities. It rises slowly and almost linearly and forms the baseline.
  2. Decomposition potential: here the species starts to be reduced, for example Cd²+ + 2e⁻ + Hg → Cd(Hg). The current rises steeply, and the concentration of the ion at the drop surface, c₀, falls below the bulk value C (concentration polarisation).
  3. Limiting current, iₗ: at more negative potentials c₀=0. Every ion is reduced as soon as it arrives, so the current is set by the rate of diffusion and stops rising with potential: the plateau. iₗ=iᵣ+i_d.
  4. Diffusion current, i_d=iₗ-iᵣ: given by the Ilkovič equation, i_d=607 n D^(1/2)m^(2/3)t^(1/6)C (mean current in µA; D in cm² s⁻¹, m in mg s⁻¹, t in s, C in mmol L⁻¹); 708 replaces 607 for the maximum current of each drop. For one capillary and one medium i_d=kC, so the height of the wave gives the concentration.
  5. Half-wave potential, E_(1/2): the potential at i=i_d/2. For a reversible wave it is close to the standard potential of the couple and does not depend on concentration. In 0.1 M KCl against the saturated calomel electrode, Cd²+ gives about -0.60 V and Zn²+ about -1.00 V.
  6. Wave equation (Heyrovský–Ilkovič): E=E_(1/2)+(0.0592)/(n)log(i_d-i)/(i) at 25°C. A plot of E against log[(i_d-i)/i] is a straight line of slope 0.0592/n V (0.0296 V for Cd²+), which gives n and tests reversibility.
  7. Oscillations: the current grows as each drop grows and falls when it detaches, so the curve is saw-toothed. A slow (damped) galvanometer records the mean.

Conditions for a clean wave: a 50 to 100 times excess of supporting electrolyte (KCl) carries the migration current, so the ion arrives by diffusion only; dissolved O₂ gives its own waves and is swept out with N₂; a maximum suppressor (a trace of gelatin or Triton X-100) removes current peaks at the top of the wave.

Application. ions whose half-wave potentials differ by about 0.2 V give separate waves, so traces of Pb²+, Cd²+ and Zn²+ are determined in one run. Holding the potential on a plateau while a titrant is added gives an amperometric titration.

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Model answer to Q4(a), 2026 Paper I: solution page 22
Solution page 22 of 55