UPSC Civil Services (Mains), Chemistry optional · 2026 · Paper I
Q5(c). Resonance structures of the nitrate ion
Question
Provide the resonance structures with formal charges for the nitrate ion.
Answer in brief
Three equivalent structures, each with one N=O and two N–O; formal charges N +1, double-bonded O 0, each single-bonded O -1. The hybrid has three equal bonds of order 4/3.
Key points
- N forms three σ bonds and one π bond. The π bond can sit on any O, giving three equivalent structures; only electrons move, not nuclei.
- FC=V-(unshared electrons)-(bonds) 3pt] N: 5-0-4=+1; O in N=O: 6-4-2=0; O in N–O: 6-6-1=-1.
- Sum: +1+0+2(-1)=-1, the charge of the ion.
- all three N–O bonds are equal (122 pm), each of bond order 4/3, and each O carries -2/3; planar D₃ₕ, like CO₃²-.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
- N forms three σ bonds and one π bond. The π bond can sit on any O, giving three equivalent structures; only electrons move, not nuclei.
- Formal charges: FC=V-(unshared electrons)-(bonds) 3pt] N: 5-0-4=+1; O in N=O: 6-4-2=0; O in N–O: 6-6-1=-1.
- Sum: +1+0+2(-1)=-1, the charge of the ion.
- The real ion is the resonance hybrid: all three N–O bonds are equal (122 pm), each of bond order 4/3, and each O carries -2/3; planar D₃ₕ, like CO₃²-.
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All parts of Question 5
- 5(a) de Broglie wavelength of a baseball5 marks
- 5(b) cis- and trans-dichloroethylene from dipole moments5 marks
- 5(c) Resonance structures of the nitrate ion5 marks
- 5(d) Spacing of the (111) planes of a simple cubic lattice5 marks
- 5(e) Ferredoxins and their classification5 marks
- 5(f) Chelate effect and chelate ring size5 marks
- 5(g) Ferrocene, the sandwich compound5 marks
- 5(h) Ionisation isomerism, and three pairs of isomers5 marks
- 5(i) Borazine, the “inorganic benzene”5 marks
- 5(j) Actinide contraction5 marks