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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper I covers physical and inorganic chemistry.

UPSC Civil Services (Mains), Chemistry optional · 2026 · Paper I

Q6(b)(ii). EAN rule; EAN of four complexes

  • 10 marks
  • Answered
Question

What is EAN rule? Calculate the EAN value of the following:
(1) [Cr(CO)₆] (2) [Fe(CN)₆]⁴- (3) [Co(NH₃)₆]³+ (4) [Ni(NH₃)₆]²+

Answer in brief

EAN = Z - (electrons lost in forming the ion) + (electrons donated by the ligands). EAN: (1) 36, (2) 36, (3) 36, (4) 38. The first three reach krypton; [Ni(NH₃)₆]²+ does not obey the rule.

Key points

  • EAN rule (Sidgwick). The effective atomic number is the total number of electrons around the metal in a complex, its own electrons plus those its ligands donate. A complex is expected to be stable when the EAN equals the…
  • EAN =Z-x+2n, where x is the oxidation state of the metal and n the number of donor pairs (n=6 for each complex here, 2n=12).

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

  1. EAN rule (Sidgwick). The effective atomic number is the total number of electrons around the metal in a complex, its own electrons plus those its ligands donate. A complex is expected to be stable when the EAN equals the atomic number of the next noble gas (36 for the 3d metals, krypton).
  2. EAN =Z-x+2n, where x is the oxidation state of the metal and n the number of donor pairs (n=6 for each complex here, 2n=12).
ComplexMetal, ZZ-x+2nEANResult
[Cr(CO)₆]Cr(0), 24241236= Kr, obeys
[Fe(CN)₆]⁴-Fe(II), 26241236= Kr, obeys
[Co(NH₃)₆]³+Co(III), 27241236= Kr, obeys
[Ni(NH₃)₆]²+Ni(II), 28261238exceeds Kr by 2, does not obey

Why the fourth complex still exists: Ni(II) is d⁸, t_(2g)⁶e_g²; the two electrons beyond 36 sit in the e_g orbitals. NH₃ is a moderate σ donor and no π acceptor, so e_g is only weakly antibonding and the complex is stable but labile. It has two unpaired electrons and is paramagnetic (μₛ=√8=2.83 μ_B). The EAN rule is a guide, not a law: [Zn(en)₃]²+ (EAN 40) is also stable.

Link with the 18-electron rule. Counting only valence electrons (metal d electrons + 12 from the ligands) gives 18 for the first three and 20 for [Ni(NH₃)₆]²+: the 18-electron rule is the EAN rule written for the valence shell. Nine bonding MOs (six σ, three t_(2g)) hold 18 electrons. It works best with strong σ-donor, π-acceptor ligands such as CO and CN⁻: Cr(CO)₆ is colourless, air-stable and sublimes unchanged, while the 17- and 19-electron ions [Cr(CO)₆]^(±) are much less stable.

Application. the rule predicts the formulas of metal carbonyls: Ni(CO)₄, Fe(CO)₅ and Cr(CO)₆ all have EAN 36. Ni(CO)₄, formed from Ni and CO at 50°C and 1 atm, is the basis of the Mond process for refining nickel.

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Model answer to Q6(b)(ii), 2026 Paper I: solution page 38
Solution page 38 of 55