Q6(b)(ii). EAN rule; EAN of four complexes
What is EAN rule? Calculate the EAN value of the following:
(1) [Cr(CO)₆] (2) [Fe(CN)₆]⁴- (3) [Co(NH₃)₆]³+ (4) [Ni(NH₃)₆]²+
Answer in brief
EAN = Z - (electrons lost in forming the ion) + (electrons donated by the ligands). EAN: (1) 36, (2) 36, (3) 36, (4) 38. The first three reach krypton; [Ni(NH₃)₆]²+ does not obey the rule.
Key points
- EAN rule (Sidgwick). The effective atomic number is the total number of electrons around the metal in a complex, its own electrons plus those its ligands donate. A complex is expected to be stable when the EAN equals the…
- EAN =Z-x+2n, where x is the oxidation state of the metal and n the number of donor pairs (n=6 for each complex here, 2n=12).
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
- EAN rule (Sidgwick). The effective atomic number is the total number of electrons around the metal in a complex, its own electrons plus those its ligands donate. A complex is expected to be stable when the EAN equals the atomic number of the next noble gas (36 for the 3d metals, krypton).
- EAN =Z-x+2n, where x is the oxidation state of the metal and n the number of donor pairs (n=6 for each complex here, 2n=12).
| Complex | Metal, Z | Z-x | +2n | EAN | Result |
| [Cr(CO)₆] | Cr(0), 24 | 24 | 12 | 36 | = Kr, obeys |
| [Fe(CN)₆]⁴- | Fe(II), 26 | 24 | 12 | 36 | = Kr, obeys |
| [Co(NH₃)₆]³+ | Co(III), 27 | 24 | 12 | 36 | = Kr, obeys |
| [Ni(NH₃)₆]²+ | Ni(II), 28 | 26 | 12 | 38 | exceeds Kr by 2, does not obey |
Why the fourth complex still exists: Ni(II) is d⁸, t_(2g)⁶e_g²; the two electrons beyond 36 sit in the e_g orbitals. NH₃ is a moderate σ donor and no π acceptor, so e_g is only weakly antibonding and the complex is stable but labile. It has two unpaired electrons and is paramagnetic (μₛ=√8=2.83 μ_B). The EAN rule is a guide, not a law: [Zn(en)₃]²+ (EAN 40) is also stable.
Link with the 18-electron rule. Counting only valence electrons (metal d electrons + 12 from the ligands) gives 18 for the first three and 20 for [Ni(NH₃)₆]²+: the 18-electron rule is the EAN rule written for the valence shell. Nine bonding MOs (six σ, three t_(2g)) hold 18 electrons. It works best with strong σ-donor, π-acceptor ligands such as CO and CN⁻: Cr(CO)₆ is colourless, air-stable and sublimes unchanged, while the 17- and 19-electron ions [Cr(CO)₆]^(±) are much less stable.
Application. the rule predicts the formulas of metal carbonyls: Ni(CO)₄, Fe(CO)₅ and Cr(CO)₆ all have EAN 36. Ni(CO)₄, formed from Ni and CO at 50°C and 1 atm, is the basis of the Mond process for refining nickel.
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All parts of Question 6
- 6(a)(i) Lewis structures and VSEPR shapes of SO₂, I₃⁻, SF₄, BrF₅, XeF₄10 marks
- 6(a)(ii) MO diagram of F₂; bond order and magnetism10 marks
- 6(b)(i) Pale pink [Co(H₂O)₆]²+ and deep blue [CoCl₄]²-10 marks
- 6(b)(ii) EAN rule; EAN of four complexes10 marks
- 6(c) Quadruple bond and bond order 4 in [Re₂Cl₈]²-10 marks