Q1(a). Azulene: resonance structures and dipole moment
Write the resonating structures of azulene and explain why it exhibits dipole moment ( 1.0 D).
Answer in brief
Azulene is a resonance hybrid of two covalent forms and a dipolar form in which a tropylium cation is fused to a cyclopentadienide anion. Both rings are then aromatic sextets, so the dipolar form contributes heavily; the electron drift towards the five-membered ring gives μ≈1.0 D.
Key points
- the seven-membered ring is a tropylium cation (6π, aromatic) and the five-membered ring a cyclopentadienide anion (6π, aromatic).
- Because the charge-separated form gives two aromatic sextets, it contributes strongly to the hybrid. Electron density is drawn from the seven-membered ring into the five-membered ring.
- The result is a permanent charge separation: the five-membered ring is the negative end and the seven-membered ring the positive end, so μ≈1.0 D.
- Naphthalene has two identical six-membered rings; no such shift is possible and μ = 0.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. Azulene (C₁₀H₈) is a blue hydrocarbon isomeric with naphthalene: a seven-membered ring fused to a five-membered ring. Its ten π electrons run round the periphery (4n+2, n=2), so it is aromatic, but unlike naphthalene it has a dipole moment of about 1.0 D.
Resonance structures
Scheme: I and II: covalent Kekulé forms. III: tropylium cation (7-ring) fused to cyclopentadienide anion (5-ring); the + and - are spread over each ring.
Forms I and II are the two covalent Kekulé structures. A shift of the shared π pair towards the five-membered ring gives the dipolar form III, and further forms place the + on C-4, C-6, C-8 and the - on C-1 and C-3.
Why azulene has a dipole moment
- In III each ring holds six π electrons: the seven-membered ring is a tropylium cation (6π, aromatic) and the five-membered ring a cyclopentadienide anion (6π, aromatic).
- Because the charge-separated form gives two aromatic sextets, it contributes strongly to the hybrid. Electron density is drawn from the seven-membered ring into the five-membered ring.
- The result is a permanent charge separation: the five-membered ring is the negative end and the seven-membered ring the positive end, so μ≈1.0 D.
- Naphthalene has two identical six-membered rings; no such shift is possible and μ = 0.
Chemical evidence for the polarisation: electrophiles (nitration, acylation, azo coupling) attack C-1 and C-3 of the electron-rich five-membered ring, while nucleophiles (organolithium reagents) add at C-4, C-6 or C-8 of the seven-membered ring.
Conclusion. Azulene is a resonance hybrid of two covalent forms and a dipolar form in which a tropylium cation is fused to a cyclopentadienide anion. Both rings are then aromatic sextets, so the dipolar form contributes heavily; the electron drift towards the five-membered ring gives μ≈1.0 D.
Application. The same charge separation lowers the HOMO–LUMO gap, so azulene absorbs in the visible and is blue; the azulene ring is found in chamomile oil (chamazulene), used as an anti-inflammatory.
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All parts of Question 1
- 1(a) Azulene: resonance structures and dipole moment10 marks
- 1(b) Norbornene and OsO₄: exo-cis diol10 marks
- 1(c) Neighbouring nitrogen: aziridinium ion10 marks
- 1(d) 3-Chlorobut-1-ene and hydroxide: allylic substitution10 marks
- 1(e) 4-Nitrobenzaldehyde: LiAlH₄ against NaBH₄10 marks