Q3(a). Toluene to m-bromotoluene: an amino group as a temporary director
How will you carry out the following conversion?
[structure] → [structure]
Answer in brief
Toluene → 4-nitrotoluene → p-toluidine → p-methylacetanilide → 2-bromo-4-methylacetanilide → 2-bromo-4-methylaniline → diazonium salt → 3-bromotoluene. The amino group places Br and is then removed.
Key points
- Nitration of toluene gives 2- and 4-nitrotoluene; the para isomer is separated (fractional crystallisation/distillation).
- Reduction (Sn/HCl or H₂/Ni) gives 4-methylaniline (p-toluidine).
- Acetylation with acetic anhydride gives 4-methylacetanilide. -NHCOCH₃ is still a strong ortho/para director but is less activating than -NH₂, so bromination stops at monosubstitution.
- the para position of NHAc is taken by CH₃, so Br enters ortho to NHAc, which is meta to CH₃. Product: 2-bromo-4-methylacetanilide.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. CH₃ is an ortho/para director, so direct bromination of toluene gives 2- and 4-bromotoluene, never the 3-isomer. The bromine must be placed by a stronger ortho/para director that sits para to CH₃; that group (-NHCOCH₃) is afterwards removed by diazotisation and reduction (deamination).
Scheme: Steps 1–3: nitration, reduction, acetylation.
Scheme: Steps 4–5: bromination directed by NHAc, then removal of the acetyl group.
Scheme: Steps 6–7: diazotisation and replacement of N₂⁺ by H.
- Nitration of toluene gives 2- and 4-nitrotoluene; the para isomer is separated (fractional crystallisation/distillation).
- Reduction (Sn/HCl or H₂/Ni) gives 4-methylaniline (p-toluidine).
- Acetylation with acetic anhydride gives 4-methylacetanilide. -NHCOCH₃ is still a strong ortho/para director but is less activating than -NH₂, so bromination stops at monosubstitution.
- Bromination: the para position of NHAc is taken by CH₃, so Br enters ortho to NHAc, which is meta to CH₃. Product: 2-bromo-4-methylacetanilide.
- Hydrolysis (acid or base) releases the amine: 2-bromo-4-methylaniline.
- Diazotisation with NaNO₂/HCl at 0–5°C gives the arenediazonium chloride.
- Hypophosphorous acid (H₃PO₂) replaces -N₂⁺ by H (radical chain reduction), leaving 3-bromotoluene (m-bromotoluene).
Conclusion. Toluene → 4-nitrotoluene → p-toluidine → p-methylacetanilide → 2-bromo-4-methylacetanilide → 2-bromo-4-methylaniline → diazonium salt → 3-bromotoluene. The amino group places Br and is then removed.
Application. Temporary amino or acetamido directors removed by H₃PO₂ give meta-disubstituted benzenes that cannot be made directly, such as 1,3,5-tribromobenzene from aniline.
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All parts of Question 3
- 3(a) Toluene to m-bromotoluene: an amino group as a temporary director10 marks
- 3(b) MCPBA epoxidation of cis- and trans-but-2-ene10 marks
- 3(c) Simmons–Smith; SOCl₂ on crotyl alcohol; Beckmann rearrangement30 marks