Q6(d). Photodecarbonylation of norcamphor and bicyclo[3.2.0]heptan-3-one
Compounds A and B undergo photodecarbonylation resulting in the formation of I and II (From A) and III and IV (From B). Give their structures.
[A] → (hν) CO + I + II [B] → (hν) CO + III + IV
Answer in brief
I = bicyclo[2.1.1]hexane, II = hexa-1,5-diene; III = bicyclo[2.2.0]hexane, IV = hexa-1,5-diene.
Key points
- C1–C2 cleavage and loss of CO leave radicals at C-1 and C-3 (C₆H₁₀). Bonding C-1 to C-3 gives I = bicyclo[2.1.1]hexane; cleavage of the C-4–C-7 bond, which links the two radical-bearing arms, gives II = hexa-1,5-diene.
- loss of CO leaves radicals at C-2 and C-4, attached to the fused carbons C-1 and C-5. Closure (C-2–C-4) gives III = bicyclo[2.2.0]hexane; cleavage of C-1–C-5 (also releasing cyclobutane strain) gives IV = hexa-1,5-diene.
- All four products are C₆H₁₀ isomers; the ring-closed products are strained bicyclic alkanes that are hard to make by thermal methods.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. Photodecarbonylation of a cyclic ketone is a Norrish type I process: α-cleavage of the excited C=O gives an acyl–alkyl biradical, which loses CO. The remaining 1,4-biradical either closes (a ring smaller by one carbon) or fragments its central C–C bond to two C=C.
Scheme: From norcamphor: the two radical centres (C-1 and C-3) are 1,4-related through C-7–C-4.
Scheme: From bicyclo[3.2.0]heptan-3-one: radical centres on C-2 and C-4, linked through the C-1–C-5 bond.
- A (norcamphor, C₇H₁₀O): C1–C2 cleavage and loss of CO leave radicals at C-1 and C-3 (C₆H₁₀). Bonding C-1 to C-3 gives I = bicyclo[2.1.1]hexane; cleavage of the C-4–C-7 bond, which links the two radical-bearing arms, gives II = hexa-1,5-diene.
- B (bicyclo[3.2.0]heptan-3-one): loss of CO leaves radicals at C-2 and C-4, attached to the fused carbons C-1 and C-5. Closure (C-2–C-4) gives III = bicyclo[2.2.0]hexane; cleavage of C-1–C-5 (also releasing cyclobutane strain) gives IV = hexa-1,5-diene.
- All four products are C₆H₁₀ isomers; the ring-closed products are strained bicyclic alkanes that are hard to make by thermal methods.
Conclusion. I = bicyclo[2.1.1]hexane, II = hexa-1,5-diene; III = bicyclo[2.2.0]hexane, IV = hexa-1,5-diene.
Application. Photodecarbonylation was the first route to bicyclo[2.1.1]hexane and is still used to make strained small rings (cyclobutanes, bicyclobutanes) from easily made ketones.
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All parts of Question 6
- 6(a) Norbornadiene with TCNE; ring opening of a cis-cyclobutene10 marks
- 6(b) Thermal cyclisation of pentadienyl anion and cation10 marks
- 6(c) Photochemistry of butadiene (S1, T1) and of pentan-2-one (Norrish I, II)10 marks
- 6(d) Photodecarbonylation of norcamphor and bicyclo[3.2.0]heptan-3-one10 marks
- 6(e) Nucleosides, nucleotides; primary structure of DNA and RNA10 marks