Q7(c). UV spectra of cis- and trans-stilbene
How can you distinguish between cis and trans isomers of stilbenes from UV spectral study? Explain.
Answer in brief
trans-Stilbene: λₘax about 294 nm, high ε; cis-stilbene: about 274 nm, low ε, because steric crowding makes cis non-planar and reduces conjugation.
Key points
- both phenyl rings lie in the plane of the C=C and the whole 14π system is conjugated. The HOMO–LUMO gap is smaller, so λₘax is longer (about 294 nm), and the long, planar chromophore has a high ε.
- the two phenyl rings on the same side clash (ortho H atoms), so the rings twist out of the plane. Conjugation is reduced: λₘax is shorter (about 274 nm) and ε is markedly lower (hypsochromic and hypochromic shift).
- The isomer with the band at longer wavelength and higher intensity is therefore trans; the steric twist in cis is an example of steric inhibition of resonance seen in UV.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. Both stilbenes (1,2-diphenylethene) show an intense π→π* band of the Ph–CH=CH–Ph chromophore. Its position and intensity depend on how well the two rings conjugate with the C=C, which depends on planarity.
Figure: Sketch of the main π→π* band: trans (solid) at longer λ and higher ε than cis (dashed).
- trans-Stilbene is planar: both phenyl rings lie in the plane of the C=C and the whole 14π system is conjugated. The HOMO–LUMO gap is smaller, so λₘax is longer (about 294 nm), and the long, planar chromophore has a high ε.
- cis-Stilbene: the two phenyl rings on the same side clash (ortho H atoms), so the rings twist out of the plane. Conjugation is reduced: λₘax is shorter (about 274 nm) and ε is markedly lower (hypsochromic and hypochromic shift).
- The isomer with the band at longer wavelength and higher intensity is therefore trans; the steric twist in cis is an example of steric inhibition of resonance seen in UV.
Conclusion. trans-Stilbene: λₘax about 294 nm, high ε; cis-stilbene: about 274 nm, low ε, because steric crowding makes cis non-planar and reduces conjugation.
Application. The same planarity argument distinguishes cis and trans azobenzenes and cinnamic acids; the change in UV absorption is followed in photo-isomerisation studies (molecular switches).
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All parts of Question 7
- 7(a) Paternò–Büchi reaction; NMR of bromopropanes; IR of α-chloro ketones15 marks
- 7(b) Kishi dihydroxylation; ketal protection; Na/NH₃ on a terpene alcohol15 marks
- 7(c) UV spectra of cis- and trans-stilbene10 marks
- 7(d) Natural rubber, polystyrene, Teflon; terylene and PVC10 marks