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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2017 · Paper II

Q8(c). Birch-type reduction of α-cyperone: trans ring fusion

  • 10 marks
  • Answered
Question

Identify the product in the following reaction and provide the mechanism for the formation of the product.
[structure] → ((i) Na, NH₃, ether, (ii) NH₄Cl)

Answer in brief

Product: trans-fused 4α,10β-dimethyl-7β-isopropenyl-decalin-3-one (dihydro-α-cyperone, C₁₅H₂₄O): conjugate reduction by two electrons and two protons, H-5 trans to the angular methyl.

Key points

  • Na gives an electron to the enone LUMO; the radical anion has spin and charge spread over C-3 (O), C-4 and C-5.
  • Protonation at C-5 (β-carbon) by NH₃; a second electron converts the radical into a carbanion, i.e. the enolate (C3–C4).
  • the β-carbanion/radical centre takes up the proton (or electron pair) in the axial orientation that is perpendicular to the enolate π system (stereoelectronic control), and the ring junction formed is trans (H-5α, opposite to…
  • NH₄Cl protonates the enolate at C-4; the product isolated has the C-4 methyl equatorial (4α), the more stable epimer.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Sodium in liquid ammonia reduces the conjugated C=C of an α,β-unsaturated ketone; the isolated isopropenyl group is not touched. In fused bicyclic enones the new C–H at the ring junction is formed so that the trans-decalone results.

Scheme: The angular methyl and H-5 end up trans; the C-4 methyl takes the equatorial position.

  1. First electron: Na gives an electron to the enone LUMO; the radical anion has spin and charge spread over C-3 (O), C-4 and C-5.
  2. Protonation at C-5 (β-carbon) by NH₃; a second electron converts the radical into a carbanion, i.e. the enolate (C3–C4).
  3. Stereochemistry: the β-carbanion/radical centre takes up the proton (or electron pair) in the axial orientation that is perpendicular to the enolate π system (stereoelectronic control), and the ring junction formed is trans (H-5α, opposite to the 10β-methyl): the more stable trans-decalin.
  4. Work-up: NH₄Cl protonates the enolate at C-4; the product isolated has the C-4 methyl equatorial (4α), the more stable epimer.
  5. The isopropenyl C=C is isolated (no conjugation) and survives; the C=O survives as the enolate.

Conclusion. Product: trans-fused 4α,10β-dimethyl-7β-isopropenyl-decalin-3-one (dihydro-α-cyperone, C₁₅H₂₄O): conjugate reduction by two electrons and two protons, H-5 trans to the angular methyl.

Application. Lithium/ammonia reduction of steroid and terpene enones (Stork) is the standard way to set trans A/B ring fusions, e.g. in making 5α-androstan-3-ones from testosterone.

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Model answer to Q8(c), 2017 Paper II: book edition page 33
Book edition, page 33