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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2018 · Paper II

Q3(c). Indenone, Wittig and octalone mechanisms

  • 15 marks
  • Answered
Question

Write the mechanism of the following:
(i) [structure] → (PhMgBr) → (H₂SO₄, Δ) [structure]
(ii) [structure] → (CH₂=CH-CH=PPh₃, Δ)
(iii) [structure] → (1) H₂SO₄–MeOH, 2) H₃O⁺) [structure]

Answer in brief

(i) Grignard addition and ring opening, intramolecular aldol, E1 dehydration: 2,3-diphenylinden-1-one. (ii) Wittig olefination: 2-(buta-1,3-dienyl)-1H-pyrrole + Ph₃P=O. (iii) Deacetylation, dienolisation, loss of the 2-OH as a pentadienyl cation, capture at C-6 and tautomerisation: the 3,6-dione.

Key points

  • PhMgBr adds to the lactone C=O: a tetrahedral alkoxide.
  • the C–O bond to the enol-ether carbon breaks, releasing an enolate of a benzyl ketone; on work-up the enol tautomerises: 1-(2-benzoylphenyl)-2-phenylethan-1-one (a 1,4-diketone).
  • the benzylic CH₂ enolises; the enol attacks the protonated benzophenone C=O (intramolecular aldol, 5-membered ring): 3-hydroxy-2,3-diphenylindan-1-one.
  • the tertiary, doubly benzylic OH leaves easily; loss of the C-2 H gives the conjugated indenone.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Three carbonyl mechanisms: (i) Grignard addition to a lactone, then an intramolecular aldol and dehydration; (ii) a Wittig olefination with an allylic ylide; (iii) an acid-catalysed isomerisation of an α-acetoxy enone (the starting alcohol and the dione have the same formula, C₁₁H₁₆O₂), which moves the oxidation level from C-2 to C-6 through dienol intermediates.

(i) 3-Benzylidenephthalide → 2,3-diphenylinden-1-one

  1. PhMgBr adds to the lactone C=O: a tetrahedral alkoxide.
  2. The ring reopens: the C–O bond to the enol-ether carbon breaks, releasing an enolate of a benzyl ketone; on work-up the enol tautomerises: 1-(2-benzoylphenyl)-2-phenylethan-1-one (a 1,4-diketone).
  3. H₂SO₄: the benzylic CH₂ enolises; the enol attacks the protonated benzophenone C=O (intramolecular aldol, 5-membered ring): 3-hydroxy-2,3-diphenylindan-1-one.
  4. E1 dehydration: the tertiary, doubly benzylic OH leaves easily; loss of the C-2 H gives the conjugated indenone.

Scheme: Atom balance: C₁₅H₁₀O₂ + Ph → C₂₁H₁₆O₂ (diketone) → C₂₁H₁₄O + H₂O.

(ii) Pyrrole-2-carbaldehyde with CH₂=CH-CH=PPh₃

Reading of the question: no product is printed; the neutral allylic ylide is taken as a Wittig partner.

  1. The ylide carbon (nucleophilic) adds to the aldehyde C=O: a betaine / directly a four-membered oxaphosphetane ([2+2]).
  2. The oxaphosphetane collapses (syn cycloreversion), driven by the strong P=O bond: Ph₃P=O is expelled and the new C=C forms.
  3. Product: 2-(buta-1,3-dien-1-yl)-1H-pyrrole, C₈H₉N. The allylic ylide is semi-stabilised, so E and Z isomers form; E is favoured on heating.
  4. Heat is needed because the pyrrole aldehyde is a vinylogous amide (N lone pair conjugated to C=O), so its C=O is a weak electrophile.

Scheme: Wittig olefination.

If instead the butadienylphosphonium salt and a base were used, the pyrrolide nitrogen would first add to the vinylphosphonium (conjugate addition) and an intramolecular Wittig would close a new N-containing ring (Schweizer annulation).

(iii) 2-Acetoxy-10-methyl-Δ⁴-octal-3-one → 10-methyldecalin-3,6-dione

  1. H₂SO₄–MeOH removes the acetyl group (acid-catalysed transesterification): 2-hydroxy-Δ⁴-3-ketone (C₁₁H₁₆O₂).
  2. The enone forms its heteroannular dienol (3-hydroxy-3,5-diene; in MeOH partly the 3-methoxy dienol ether): H is removed from C-6.
  3. The 2-OH is now allylic to the C3=C4 bond; protonated, it leaves as water to give a pentadienyl cation spread over C-2, C-4 and C-6.
  4. Methanol (or water) adds at the C-6 terminus; the C-3 enol then reverts to the ketone with C-2 as a CH₂: 6-methoxy (6-hydroxy)-Δ⁴-3-ketone.
  5. Step 2, H₃O⁺: dienolisation again (loss of H-6) gives the enol ether / enol of a C-6 ketone; hydrolysis and protonation at C-4 and C-5 give the saturated 3,6-dione, with the C-5 H trans to the angular methyl (trans ring fusion).

Scheme: The oxygen function is moved from C-2 to C-6 through dienols; one resonance form of the cation is drawn.

Conclusion. (i) Grignard addition and ring opening, intramolecular aldol, E1 dehydration: 2,3-diphenylinden-1-one. (ii) Wittig olefination: 2-(buta-1,3-dienyl)-1H-pyrrole + Ph₃P=O. (iii) Deacetylation, dienolisation, loss of the 2-OH as a pentadienyl cation, capture at C-6 and tautomerisation: the 3,6-dione.

Application. Indenones and 2,3-diarylindenones are oestrogen-receptor ligands; dienol and dienol-ether chemistry of Δ⁴-3-keto steroids is used industrially to introduce oxygen at C-6 of corticosteroids.

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Model answer to Q3(c), 2018 Paper II: book edition page 14
Book edition, page 14
Model answer to Q3(c), 2018 Paper II: book edition page 15
Book edition, page 15
Model answer to Q3(c), 2018 Paper II: book edition page 16
Book edition, page 16