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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2018 · Paper II

Q5(b). Allylic SN1: kinetic and thermodynamic acetates

  • 10 marks
  • Answered
Question

Two substitution products result from the reaction of 3-chloro-3-methyl-1-butene with sodium acetate (CH₃COO-Na⁺) in acetic acid under SN1 conditions. Identify the products. Indicate the thermodynamic product and kinetic product.

Answer in brief

Products: 2-methylbut-3-en-2-yl acetate (kinetic) and 3-methylbut-2-en-1-yl acetate (thermodynamic), both from the same resonance-stabilised allylic cation.

Key points

  • Cl⁻ leaves to give the 1,1-dimethylallyl cation, (CH₃)₂C+-CH=CH₂ <→ (CH₃)₂C=CH-CH₂⁺.
  • Attack at the tertiary carbon (C-3) gives 2-methylbut-3-en-2-yl acetate, CH₂=CH-C(CH₃)₂-OAc. The tertiary carbon carries the larger share of the positive charge, and the acetate is close to it in the ion pair just after Cl…
  • Attack at the primary carbon (C-1) gives 3-methylbut-2-en-1-yl acetate (prenyl acetate), (CH₃)₂C=CH-CH₂-OAc. Its C=C is trisubstituted (more hyperconjugation) and the acetate is on an unhindered primary carbon, so it is more…
  • With longer reaction time or heat, the tertiary allylic acetate re-ionises (it is a good SN1 substrate) and the mixture drifts to the primary acetate.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Under SN1 conditions the tertiary allylic chloride ionises to an allylic cation with two resonance forms; acetate can attack either end, so two isomeric acetates form (allylic rearrangement).

Scheme: The 1,1-dimethylallyl cation is attacked at the tertiary (C-3) or primary (C-1) end.

  1. Ionisation (rate-determining): Cl⁻ leaves to give the 1,1-dimethylallyl cation, (CH₃)₂C+-CH=CH₂ <→ (CH₃)₂C=CH-CH₂⁺.
  2. Attack at the tertiary carbon (C-3) gives 2-methylbut-3-en-2-yl acetate, CH₂=CH-C(CH₃)₂-OAc. The tertiary carbon carries the larger share of the positive charge, and the acetate is close to it in the ion pair just after Cl leaves, so this product forms faster: the kinetic product.
  3. Attack at the primary carbon (C-1) gives 3-methylbut-2-en-1-yl acetate (prenyl acetate), (CH₃)₂C=CH-CH₂-OAc. Its C=C is trisubstituted (more hyperconjugation) and the acetate is on an unhindered primary carbon, so it is more stable: the thermodynamic product.
  4. With longer reaction time or heat, the tertiary allylic acetate re-ionises (it is a good SN1 substrate) and the mixture drifts to the primary acetate.

Conclusion. Products: 2-methylbut-3-en-2-yl acetate (kinetic) and 3-methylbut-2-en-1-yl acetate (thermodynamic), both from the same resonance-stabilised allylic cation.

Application. Prenyl (3-methylbut-2-enyl) acetate and related allylic esters are made this way for perfumes; the same kinetic/thermodynamic choice governs 1,2- versus 1,4-addition of HBr to butadiene.

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Model answer to Q5(b), 2018 Paper II: solution page 16
Solution page 16 of 24