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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2019 · Paper II

Q1(c). Neopentyl tosylate: 1,2-methyl shift

  • 10 marks
  • Answered
Question

Neopentyl tosylate on solvolysis gives 2-methylbutan-2-ol. Write the mechanism of its formation.

Answer in brief

Solvolysis of neopentyl tosylate is SN1 with a 1,2-methyl shift: the hindered primary system ionises with methyl participation to the tertiary tert-amyl cation, and water captures it to give 2-methylbutan-2-ol (with 2-methylbut-2-ene as the E1 by-product).

Key points

  • Ionisation (rate-determining). The C–OTs bond breaks heterolytically; TsO⁻ is an excellent, resonance-stabilised leaving group. An unassisted primary cation is very unstable, so the migration of a methyl group from the…
  • 1,2-Methyl shift. A CH₃ group moves with its bonding electron pair from C-2 to C-1. C-1 becomes CH₂-CH₃ (an ethyl group) and the positive charge moves to C-2, which now carries two methyls and an ethyl: the 2-methylbutan-2-yl…
  • Capture by solvent. Water attacks the planar cation; loss of H⁺ gives 2-methylbutan-2-ol, (CH₃)₂C(OH)CH₂CH₃.
  • By-products. The same tertiary cation also loses H⁺ (E1) to give 2-methylbut-2-ene (main alkene, Saytzeff) and some 2-methylbut-1-ene. No neopentyl alcohol is formed.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Neopentyl tosylate, (CH₃)₃CCH₂OTs, is primary but very hindered: the tert-butyl group blocks back-side attack, so SN2 is extremely slow. In a polar, weakly nucleophilic solvent (water, aqueous ethanol, formic acid) the substrate ionises slowly instead, and the carbon skeleton rearranges by a 1,2-methyl shift (Wagner–Meerwein) to a tertiary cation that the solvent captures.

Scheme: SN1 with rearrangement: the methyl moves with its bonding pair to the electron-poor carbon.

  1. Ionisation (rate-determining). The C–OTs bond breaks heterolytically; TsO⁻ is an excellent, resonance-stabilised leaving group. An unassisted primary cation is very unstable, so the migration of a methyl group from the quaternary carbon assists the departure of TsO⁻ (the methyl is anti-periplanar to the C–O bond). Ionisation and migration are therefore nearly concerted.
  2. 1,2-Methyl shift. A CH₃ group moves with its bonding electron pair from C-2 to C-1. C-1 becomes CH₂-CH₃ (an ethyl group) and the positive charge moves to C-2, which now carries two methyls and an ethyl: the 2-methylbutan-2-yl (tert-amyl) cation, a tertiary cation stabilised by hyperconjugation with eight C–H bonds.
  3. Capture by solvent. Water attacks the planar cation; loss of H⁺ gives 2-methylbutan-2-ol, (CH₃)₂C(OH)CH₂CH₃.
  4. By-products. The same tertiary cation also loses H⁺ (E1) to give 2-methylbut-2-ene (main alkene, Saytzeff) and some 2-methylbut-1-ene. No neopentyl alcohol is formed.

Conclusion. Solvolysis of neopentyl tosylate is SN1 with a 1,2-methyl shift: the hindered primary system ionises with methyl participation to the tertiary tert-amyl cation, and water captures it to give 2-methylbutan-2-ol (with 2-methylbut-2-ene as the E1 by-product).

Application. The same rearrangement makes neopentyl halides useless in SN2 and SN1 synthesis and appears in Friedel–Crafts alkylation (neopentyl chloride gives tert-pentylbenzene) and in terpene and steroid rearrangements.

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Model answer to Q1(c), 2019 Paper II: solution page 4
Solution page 4 of 23