Q5(b). Baeyer–Villiger oxidation of an electron-rich aldehyde
Identify (X) and (Y) in the following reaction and outline the mechanism for the formation of (X):
[structure] → (mCPBA, CHCl₃) (X) → (H₃O⁺) (Y)
Answer in brief
X = 3,4-dimethoxyphenyl formate, formed through the Criegee intermediate by preferential migration of the electron-rich aryl group; Y = 3,4-dimethoxyphenol, by acid hydrolysis of the formate.
Key points
- Addition. The peracid adds to the C=O of 3,4-dimethoxybenzaldehyde to give the tetrahedral Criegee intermediate, ArCH(OH)-O-O-COAr'.
- Migration (rate-determining). As the weak O–O bond breaks and m-chlorobenzoate leaves, a group on the carbinol carbon moves to the electron-poor oxygen. The aryl group migrates rather than H, because the 4-OMe group (para to…
- Product. Loss of the proton from OH gives X = 3,4-dimethoxyphenyl formate, HCOO-C₆H₃(OMe)₂.
- Hydrolysis. Aqueous acid hydrolyses the formate ester: Y = 3,4-dimethoxyphenol + HCOOH.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. Peracids convert aldehydes and ketones into esters by Baeyer–Villiger oxidation. In an aldehyde the group that migrates is either H (giving a carboxylic acid) or the carbon group (giving a formate). An electron-rich aryl group (here 3,4-dimethoxyphenyl) migrates in preference to H, so the product is an aryl formate; this is the peracid version of the Dakin reaction.
Scheme: Ar in the peracid = 3-chlorophenyl; m-chlorobenzoic acid is released in the migration step.
- Addition. The peracid adds to the C=O of 3,4-dimethoxybenzaldehyde to give the tetrahedral Criegee intermediate, ArCH(OH)-O-O-COAr'.
- Migration (rate-determining). As the weak O–O bond breaks and m-chlorobenzoate leaves, a group on the carbinol carbon moves to the electron-poor oxygen. The aryl group migrates rather than H, because the 4-OMe group (para to the migrating carbon) stabilises the partial positive charge in the bridged (phenonium-like) transition state.
- Product. Loss of the proton from OH gives X = 3,4-dimethoxyphenyl formate, HCOO-C₆H₃(OMe)₂.
- Hydrolysis. Aqueous acid hydrolyses the formate ester: Y = 3,4-dimethoxyphenol + HCOOH.
Scheme: Acid hydrolysis of the formate ester.
Without the electron-donating groups (e.g. benzaldehyde itself) H migrates and the product is the carboxylic acid (here it would be 3,4-dimethoxybenzoic acid, the minor path).
Conclusion. X = 3,4-dimethoxyphenyl formate, formed through the Criegee intermediate by preferential migration of the electron-rich aryl group; Y = 3,4-dimethoxyphenol, by acid hydrolysis of the formate.
Application. This aldehyde-to-phenol sequence (Baeyer–Villiger/Dakin) is used to make catechol and hydroquinone ethers, e.g. 3,4-dimethoxyphenol from veratraldehyde for natural-product synthesis.
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All parts of Question 5
- 5(a) DNA bases and Watson–Crick pairing10 marks
- 5(b) Baeyer–Villiger oxidation of an electron-rich aldehyde10 marks
- 5(c) Photochemistry of norbornenone: 1,3-acyl shift and ketene loss10 marks
- 5(d) λ_(max) by Woodward–Fieser and Scott rules10 marks
- 5(e) IR spectra of two isoxazolone tautomers10 marks