Q7(b). Borane: acid reduced, ester kept; δ-lactone
Name the reagent for the following regioselective conversion. Propose the mechanism:
[structure] → (?) [structure]
Answer in brief
Reagent: diborane, B₂H₆ (BH₃*THF), then H₃O⁺. Borane reduces the CO₂H through an acyloxyborane to CH₂OH and leaves the ester; the 5-hydroxy ester lactonises to (S)-4-methyltetrahydropyran-2-one with retention of configuration.
Key points
- Acyloxyborane formation. Borane is an electrophilic (Lewis-acidic) hydride. The acidic O–H reacts first: RCO₂H + BH₃ → RCO₂BH₂ + H₂. Three such steps give a triacyloxyborane.
- Activation. In the acyloxyborane the C=O oxygen is bonded through boron, which lowers the electron density on the carbonyl carbon (the carboxylate resonance is lost). The carbonyl oxygen also coordinates further BH₃.
- Hydride transfer. B–H delivers hydride to the activated C=O (intramolecularly and from added BH₃): the acid is reduced through the aldehyde oxidation level to an alkoxyborane, RCH₂O-B.
- Ester untouched. The ester carbonyl oxygen is a poor Lewis base and does not bind borane well, so CO₂Et reacts only slowly: this is the chemoselectivity (regioselectivity between the two ends).
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. The two ends of the half-ester differ: one is a CO₂H, the other a CO₂Et. The lactone (4-methyltetrahydropyran-2-one) keeps the ester carbon as its C=O and needs the CO₂H end reduced to CH₂OH. The reagent that reduces a carboxylic acid in the presence of an ester is diborane (B₂H₆, or BH₃*THF), followed by acid (lactonisation).
Scheme: Borane reduces CO₂H to CH₂OH; the alcohol then closes the six-membered lactone on the ester.
- Acyloxyborane formation. Borane is an electrophilic (Lewis-acidic) hydride. The acidic O–H reacts first: RCO₂H + BH₃ → RCO₂BH₂ + H₂. Three such steps give a triacyloxyborane.
- Activation. In the acyloxyborane the C=O oxygen is bonded through boron, which lowers the electron density on the carbonyl carbon (the carboxylate resonance is lost). The carbonyl oxygen also coordinates further BH₃.
- Hydride transfer. B–H delivers hydride to the activated C=O (intramolecularly and from added BH₃): the acid is reduced through the aldehyde oxidation level to an alkoxyborane, RCH₂O-B.
- Ester untouched. The ester carbonyl oxygen is a poor Lewis base and does not bind borane well, so CO₂Et reacts only slowly: this is the chemoselectivity (regioselectivity between the two ends).
- Work-up and ring closure. Hydrolysis (H₃O⁺) releases the primary alcohol, ethyl 5-hydroxy-3-methylpentanoate. In acid the OH attacks the ester C=O (intramolecular transesterification) and EtOH is lost, closing the unstrained six-membered δ-lactone.
Stereochemistry. No bond to the stereocentre (C-3) is broken, so the configuration is kept; the (S)-half-ester gives the (S)-lactone that is printed. LiBH₄ would do the opposite: it leaves the carboxylate untouched and reduces the ester; the hydroxy acid would close to the enantiomeric lactone. (LiAlH₄ reduces both ends to the diol.)
Conclusion. Reagent: diborane, B₂H₆ (BH₃*THF), then H₃O⁺. Borane reduces the CO₂H through an acyloxyborane to CH₂OH and leaves the ester; the 5-hydroxy ester lactonises to (S)-4-methyltetrahydropyran-2-one with retention of configuration.
Application. Chemoselective borane reduction of acids in the presence of esters is used to make chiral lactones and hydroxy esters from desymmetrised glutaric acid half-esters, building blocks for statins and pheromones.
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All parts of Question 7
- 7(a) Structure of C₈H₄O₃ from IR, NMR and mass spectrum: phthalic anhydride15 marks
- 7(b) Borane: acid reduced, ester kept; δ-lactone15 marks
- 7(c) SeO₂/H₂O₂, Pb(OAc)₄, OsO₄, periodate20 marks