VKC ScienceChemistry for written exams Telegram

UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2019 · Paper II

Q8(c)(ii). Photodecarbonylation; trapping the o-xylylene

  • 10 marks
  • Answered
Question

Identify (X) and (Y) in the following reaction:
[structure] → (hν) (X) → (maleic anhydride, Δ) (Y)

Answer in brief

X = α,α'-diphenyl-o-xylylene, formed by photochemical loss of CO (Norrish type I); Y = its Diels–Alder adduct with maleic anhydride, the all-cis 1,4-diphenyltetralin-2,3-dicarboxylic anhydride.

Key points

  • α-Cleavage. The excited ketone breaks one C(O)–CHPh bond to give a benzylic radical and an acyl radical (Norrish type I). The acyl radical loses CO, leaving a 1,4-biradical (two benzylic radical centres held ortho on the ring).
  • X. The biradical closes its π system to the quinonoid diene α,α'-diphenyl-o-xylylene (5,6-dibenzylidenecyclohexa-1,3-diene), mainly the (E,E) isomer with both Ph pointing outwards. It is not aromatic and is very reactive.
  • Y. The s-cis exocyclic diene adds to maleic anhydride (suprafacial [4+2], endo). Formation of the new six-membered ring restores the aromatic sextet, a large driving force. Y =…
  • Stereochemistry of Y. The (E,E) diene puts both Ph on one face; endo addition puts the anhydride on the same face: all four substituents cis.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Indan-2-ones lose carbon monoxide on irradiation (photodecarbonylation, Norrish type I). Both bonds to the C=O are benzylic and break easily, so the product is a reactive o-quinodimethane (o-xylylene). This diene is trapped by maleic anhydride in a Diels–Alder reaction that also restores the benzene ring.

Scheme: CO is lost; the diene is trapped and the ring becomes aromatic again.

  1. α-Cleavage. The excited ketone breaks one C(O)–CHPh bond to give a benzylic radical and an acyl radical (Norrish type I). The acyl radical loses CO, leaving a 1,4-biradical (two benzylic radical centres held ortho on the ring).
  2. X. The biradical closes its π system to the quinonoid diene α,α'-diphenyl-o-xylylene (5,6-dibenzylidenecyclohexa-1,3-diene), mainly the (E,E) isomer with both Ph pointing outwards. It is not aromatic and is very reactive.
  3. Y. The s-cis exocyclic diene adds to maleic anhydride (suprafacial [4+2], endo). Formation of the new six-membered ring restores the aromatic sextet, a large driving force. Y = 1,4-diphenyl-1,2,3,4-tetrahydronaphthalene-2,3-dicarboxylic anhydride.
  4. Stereochemistry of Y. The (E,E) diene puts both Ph on one face; endo addition puts the anhydride on the same face: all four substituents cis.

Conclusion. X = α,α'-diphenyl-o-xylylene, formed by photochemical loss of CO (Norrish type I); Y = its Diels–Alder adduct with maleic anhydride, the all-cis 1,4-diphenyltetralin-2,3-dicarboxylic anhydride.

Application. Photochemical or thermal generation of o-xylylenes and trapping by dienophiles is a standard route to tetralins and to the steroid and anthracycline ring systems.

Practising this answer? Write it in a Mains test and get it checked by VKC. Civil Services Mains test series · Telegram

Model answer to Q8(c)(ii), 2019 Paper II: solution page 22
Solution page 22 of 23

All parts of Question 8