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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2020 · Paper II

Q4(a). Acid-catalysed Wagner–Meerwein aromatisation (duocarmycin B2 unit)

  • 15 marks
  • Answered
Question

Identify the product and the name reaction involved in the following conversion. Also write the mechanism involved offering suitable explanation for the choice of CH₃SO₃H for this reaction:
[structure] → (CH₃SO₃H (2.5 equiv.), DCE, 50°C) A
DCE = Dichloroethane

Answer in brief

A is the aromatic pyrrolo-indole carrying 2-CH₃ and 3-CO₂CH₃ (CH₂Br, N–R and the carbamate unchanged). It forms by a Wagner–Meerwein rearrangement (dehydration, 1,2-ester shift to an iminium ion, aromatisation). CH₃SO₃H is a strong, non-nucleophilic, non-oxidising acid that works in dry organic solvent.

Key points

  • Ionisation. CH₃SO₃H protonates the C-3 hydroxyl; water leaves and gives a secondary benzylic cation at C-3, stabilised by the aromatic ring, which carries the donor N–R group (RDS).
  • 1,2-Shift. A group on the adjacent quaternary C-2 migrates with its bonding pair to C-3 (Wagner–Meerwein shift). The group that moves is the methoxycarbonyl group. The positive charge is now on C-2, next to the ring NH, so it…
  • Why CO₂Me and not Me migrates. Moving CO₂Me leaves the electron-donating CH₃ on the cationic C-2, where it stabilises the iminium ion; moving CH₃ would leave an electron-withdrawing ester on the carbon bearing the positive…
  • Aromatisation. Loss of the C-3 proton gives the aromatic pyrrole ring of an indole. This large gain in stability is the driving force: the reaction is irreversible.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. The substrate is a reduced duocarmycin B2 derivative: its left-hand five-membered ring is an indoline with a quaternary C-2 (Me, CO₂Me, NH) and a secondary benzylic alcohol at C-3. In strong acid the alcohol ionises, a group on C-2 migrates to C-3 and the ring loses a proton to become an aromatic pyrrole (indole) ring. This dehydrative 1,2-shift is a Wagner–Meerwein rearrangement.

Scheme: Protonation of the C-3 OH and loss of water give a benzylic cation, stabilised by the electron-rich arene.

Scheme: The methoxycarbonyl group moves from C-2 to C-3; the cation at C-2 is an iminium ion; loss of the C-3 proton makes the pyrrole ring aromatic.

  1. Ionisation. CH₃SO₃H protonates the C-3 hydroxyl; water leaves and gives a secondary benzylic cation at C-3, stabilised by the aromatic ring, which carries the donor N–R group (RDS).
  2. 1,2-Shift. A group on the adjacent quaternary C-2 migrates with its bonding pair to C-3 (Wagner–Meerwein shift). The group that moves is the methoxycarbonyl group. The positive charge is now on C-2, next to the ring NH, so it is an iminium ion (C=N+H), much more stable than the benzylic cation.
  3. Why CO₂Me and not Me migrates. Moving CO₂Me leaves the electron-donating CH₃ on the cationic C-2, where it stabilises the iminium ion; moving CH₃ would leave an electron-withdrawing ester on the carbon bearing the positive charge. An acyl group also migrates easily because its C=O π system helps bridge the two carbons in the transition state.
  4. Aromatisation. Loss of the C-3 proton gives the aromatic pyrrole ring of an indole. This large gain in stability is the driving force: the reaction is irreversible.
  5. Product A. The pyrrolo[3,2-e]indole with 2-methyl and 3-methoxycarbonyl groups on the new pyrrole ring; the CH₂Br, N–R and the 4-methylpiperazine carbamate are unchanged. C-2 and C-3 are no longer stereocentres. (This is the step that converts reduced duocarmycin B2 into the antitumour prodrug KW-2189.)

Why methanesulfonic acid

  1. It is a strong acid (comparable with H₂SO₄), so it ionises a secondary alcohol at only 50°C.
  2. Its conjugate base, mesylate, is non-nucleophilic: it does not trap the benzylic cation (HCl or HBr would give the benzylic halide) and does not displace bromide from the CH₂Br group.
  3. It is non-oxidising and can be used anhydrous in dichloroethane; no water is present to hydrolyse the methyl ester or the carbamate, as aqueous mineral acids would.
  4. 2.5 equivalents are needed because the basic N-methylpiperazine nitrogen (and partly the ring nitrogens) take up acid first; the excess acid catalyses the rearrangement.

Conclusion. A is the aromatic pyrrolo-indole carrying 2-CH₃ and 3-CO₂CH₃ (CH₂Br, N–R and the carbamate unchanged). It forms by a Wagner–Meerwein rearrangement (dehydration, 1,2-ester shift to an iminium ion, aromatisation). CH₃SO₃H is a strong, non-nucleophilic, non-oxidising acid that works in dry organic solvent.

Application. The duocarmycins and CC-1065 are DNA-alkylating antitumour agents; converting the unstable natural product into a stable aromatic seco form, as here, is how the clinical prodrug KW-2189 was made.

Practising this answer? Write it in a Mains test and get it checked by VKC. Civil Services Mains test series · Telegram

Model answer to Q4(a), 2020 Paper II: book edition page 13
Book edition, page 13
Model answer to Q4(a), 2020 Paper II: book edition page 14
Book edition, page 14
Model answer to Q4(a), 2020 Paper II: book edition page 15
Book edition, page 15

All parts of Question 4