Q5(c). Photoenolisation and intramolecular Diels–Alder: estrone skeleton
Complete the following reaction giving the structures of intermediates involved:
[structure] → (hν (λ> 340 nm), Py, Mesitol) ?
Answer in brief
Intermediates: the excited ketone, the 1,4-biradical and the E-photoenol (hydroxy-o-quinodimethane). Product: 9α-hydroxyestrone 3-methyl ether, formed by photoenolisation followed by an intramolecular Diels–Alder reaction.
Key points
- Excitation. Light above 340 nm is absorbed only by the aryl ketone (n→π*); the cyclopentanone and the product do not absorb, so they are not destroyed.
- Hydrogen abstraction. The half-filled n orbital of the excited oxygen removes a hydrogen from the o-CH₃ through a six-membered transition state (a 1,5-H shift, Norrish type II-like), giving a 1,4-biradical that collapses to…
- E and Z photoenols. The Z-enol (OH towards the CH₂) returns quickly to the ketone; the longer-lived E-photoenol is the reactive diene.
- Diels–Alder. The tethered vinyl group is the dienophile. The o-CH₂ bonds to its terminal carbon (C-7) and the carbinol carbon bonds to its internal carbon (C-8), closing the new six-membered ring B and, through the tether,…
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. An aryl ketone with an ortho-methyl group undergoes photoenolisation: light gives the excited ketone, which takes an H atom from the o-methyl group to form a hydroxy-o-quinodimethane (a photoenol). This reactive diene is trapped by the vinyl group of the same molecule in an intramolecular Diels–Alder reaction that builds rings B and C of a steroid in one step (Quinkert's estrone synthesis).
Scheme: Excited C=O abstracts an H from the o-CH₃ (via a 1,4-biradical); the E-photoenol is the diene.
Scheme: The diene termini (o-CH₂ and the carbinol carbon) bond to the two carbons of the vinyl group: rings B and C form together.
- Excitation. Light above 340 nm is absorbed only by the aryl ketone (n→π*); the cyclopentanone and the product do not absorb, so they are not destroyed.
- Hydrogen abstraction. The half-filled n orbital of the excited oxygen removes a hydrogen from the o-CH₃ through a six-membered transition state (a 1,5-H shift, Norrish type II-like), giving a 1,4-biradical that collapses to the photoenol.
- E and Z photoenols. The Z-enol (OH towards the CH₂) returns quickly to the ketone; the longer-lived E-photoenol is the reactive diene.
- Diels–Alder. The tethered vinyl group is the dienophile. The o-CH₂ bonds to its terminal carbon (C-7) and the carbinol carbon bonds to its internal carbon (C-8), closing the new six-membered ring B and, through the tether, ring C at the same time. The exo transition state sets the trans B/C fusion (8β-H, 9α-OH); the trans C/D relationship (13β-CH₃, 14α-H) is already present in the starting ketone.
- Product. 9α-hydroxy-3-methoxyestra-1,3,5(10)-trien-17-one (9α-hydroxyestrone 3-methyl ether). Pyridine and mesitol are added to the irradiated solution to suppress acid-catalysed side reactions of the photoenol and of the tertiary alcohol.
Conclusion. Intermediates: the excited ketone, the 1,4-biradical and the E-photoenol (hydroxy-o-quinodimethane). Product: 9α-hydroxyestrone 3-methyl ether, formed by photoenolisation followed by an intramolecular Diels–Alder reaction.
Application. Dehydration of the 9α-alcohol and reduction lead to estrone, the female sex hormone; photoenol Diels–Alder reactions are a general route to the tetralin rings of steroids and anthracyclines.
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All parts of Question 5
- 5(a) Tetrafluoroethylene from methane; uses of PTFE10 marks
- 5(b) Chemoselective reduction: NaBH₄ then LiAlH₄10 marks
- 5(c) Photoenolisation and intramolecular Diels–Alder: estrone skeleton10 marks
- 5(d) Aromatic out-of-plane C–H wagging and adjacent hydrogens10 marks
- 5(e) Methyl groups of 7,7-dimethylnorbornene: anisotropy of C=C10 marks