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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2020 · Paper II

Q6(b). o-Xylylene from a tetrabromide; photochemical ring closure

  • 15 marks
  • Answered
Question

Complete the conversion given below writing intermediate steps involved:
[structure] → (1) I⁻, 2) hν) ?

Answer in brief

I⁻ effects 1,4-debromination to (E,E)-α,α'-dibromo-o-xylylene; hν closes it by a disrotatory 4π electrocyclisation to cis-1,2-dibromobenzocyclobutene (the thermal, conrotatory route gives the trans isomer).

Key points

  • Debromination. I⁻ attacks a bromine atom of one CHBr₂ group (halophilic attack, giving IBr, which reacts with more iodide to I₂ and Br⁻). The carbanion formed pushes its electrons through the ring and expels Br⁻ from the other…
  • Intermediate. α,α'-Dibromo-o-xylylene (5,6-bis(bromomethylidene)cyclohexa-1,3-diene). The ring has lost its aromaticity, so the diene is very reactive. The bulky Br atoms prefer the outward (E,E) positions.
  • Photochemical closure. The terminal =CHBr carbons form a σ bond: a 4π electrocyclic ring closure. Under irradiation the HOMO is ψ₃, whose end lobes are in phase on the same face, so the closure is disrotatory.
  • Stereochemistry. Disrotation of the (E,E) diene turns both outward Br atoms the same way: the product is cis-1,2-dibromobenzocyclobutene. Closure is strongly favoured because it regenerates the benzene ring.

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Iodide removes two bromine atoms from the two CHBr₂ groups by a 1,4-elimination, generating the reactive diene α,α'-dibromo-o-xylylene (an o-quinodimethane). Light then closes it by a 4π electrocyclic reaction to a benzocyclobutene; closure restores the aromatic ring.

Scheme: Debromination gives an o-quinodimethane; photochemical 4π closure is disrotatory.

  1. Debromination. I⁻ attacks a bromine atom of one CHBr₂ group (halophilic attack, giving IBr, which reacts with more iodide to I₂ and Br⁻). The carbanion formed pushes its electrons through the ring and expels Br⁻ from the other CHBr₂ group: a 1,4-elimination.
  2. Intermediate. α,α'-Dibromo-o-xylylene (5,6-bis(bromomethylidene)cyclohexa-1,3-diene). The ring has lost its aromaticity, so the diene is very reactive. The bulky Br atoms prefer the outward (E,E) positions.
  3. Photochemical closure. The terminal =CHBr carbons form a σ bond: a 4π electrocyclic ring closure. Under irradiation the HOMO is ψ₃, whose end lobes are in phase on the same face, so the closure is disrotatory.
  4. Stereochemistry. Disrotation of the (E,E) diene turns both outward Br atoms the same way: the product is cis-1,2-dibromobenzocyclobutene. Closure is strongly favoured because it regenerates the benzene ring.
  5. Contrast. Without light (warming with NaI in ethanol), the same o-xylylene closes conrotatorily and gives trans-1,2-dibromobenzocyclobutene; the two routes show the thermal/photochemical switch of the Woodward–Hoffmann rules.

Conclusion. I⁻ effects 1,4-debromination to (E,E)-α,α'-dibromo-o-xylylene; hν closes it by a disrotatory 4π electrocyclisation to cis-1,2-dibromobenzocyclobutene (the thermal, conrotatory route gives the trans isomer).

Application. Benzocyclobutenes made this way reopen on heating to o-xylylenes, which are trapped in Diels–Alder reactions to build steroid and anthracycline ring systems.

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Model answer to Q6(b), 2020 Paper II: solution page 15
Solution page 15 of 21

All parts of Question 6