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UPSC Civil Services (Mains)

Chemistry optional

  • 2 papers
  • 250 marks each
  • 3 h per paper
  • 5 of 8 questions, Q1 and Q5 compulsory

Paper II covers organic chemistry and spectroscopy.

UPSC Civil Services (Mains), Chemistry optional · 2020 · Paper II

Q7(b). Length of an α-helix and of B-DNA; effect of denaturation

  • 15 marks
  • Answered
Question

Compare the length of an α-helix that contains 74 amino acids with that of a B-DNA having same number of base pairs. Also mention if the lengths of these biopolymers increase or decrease on denaturation.

Answer in brief

α-helix (74 residues) = 111 Å (11.1 nm); B-DNA (74 bp) = 251.6 Å (25.2 nm), about 2.3 times longer. On denaturation the polypeptide lengthens (helix → extended chain, up to 3.5 Å per residue), while DNA shortens (rigid duplex → coiled single strands).

Key points

  • Comparison. The α-helix (20.6 turns) is a compact coil, 11.1 nm long; B-DNA with the same number of units (7.4 turns) is about 2.3 times longer, 25.2 nm, because the stacked base pairs are 3.4 Å apart while amino acid residues…
  • length increases. Heat, urea or extreme pH breaks the intrachain C=O…H–N hydrogen bonds (between residues i and i+4). The helix unwinds into an extended chain in which consecutive residues are up to 3.5 Å apart, so the contour…
  • length decreases. Heating above the melting temperature breaks the interstrand base-pair hydrogen bonds and base stacking; the two strands separate (hyperchromic effect in the UV). The rigid, rod-like 25 nm duplex is replaced…

The full model answer

Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.

Introduction. Both are helices whose length is set by the rise per unit along the axis. An α-helix has 3.6 residues per turn and a pitch of 5.4 Å, i.e. a rise of 1.5 Å per residue. B-DNA has 10 base pairs per turn and a rise of 3.4 Å per base pair.

Given: n = 74 residues or base pairs; rise 5.4/3.6 = 1.5 Å per residue (α-helix); 3.4 Å per base pair (B-DNA).

L_α=74×1.5 Å=111 Å=11.1 nm L_(DNA)=74×3.4 Å=251.6 Å≈25.2 nm

L_DNA/L_α = 3.4/1.5 ≈ 2.27

Figure: Same number of units: the DNA double helix is about 2.3 times longer.

  1. Comparison. The α-helix (20.6 turns) is a compact coil, 11.1 nm long; B-DNA with the same number of units (7.4 turns) is about 2.3 times longer, 25.2 nm, because the stacked base pairs are 3.4 Å apart while amino acid residues advance only 1.5 Å.
  2. Protein on denaturation: length increases. Heat, urea or extreme pH breaks the intrachain C=O…H–N hydrogen bonds (between residues i and i+4). The helix unwinds into an extended chain in which consecutive residues are up to 3.5 Å apart, so the contour length can rise from 111 Å to about 259 Å (74 × 3.5 Å).
  3. DNA on denaturation: length decreases. Heating above the melting temperature breaks the interstrand base-pair hydrogen bonds and base stacking; the two strands separate (hyperchromic effect in the UV). The rigid, rod-like 25 nm duplex is replaced by two flexible single strands that collapse into random coils, whose end-to-end length is much shorter.

Conclusion. α-helix (74 residues) = 111 Å (11.1 nm); B-DNA (74 bp) = 251.6 Å (25.2 nm), about 2.3 times longer. On denaturation the polypeptide lengthens (helix → extended chain, up to 3.5 Å per residue), while DNA shortens (rigid duplex → coiled single strands).

Application. These dimensions explain why a protein helix of about 20 residues (3 nm) just spans a cell membrane and why the double helix packs 3.4 Å per base pair into chromatin; DNA melting curves are used to measure GC content.

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Model answer to Q7(b), 2020 Paper II: solution page 18
Solution page 18 of 21

All parts of Question 7