Q5(d). LiAlH₄ reduction of camphor: OH cis to the bridge
Reduction of camphor with LiAlH₄ leads to 90% of the isomer in which the OH group is cis to the bridge. Give a suitable explanation of this observation.
Answer in brief
Hydride attacks C=O from the less hindered endo face; the syn-7-methyl group of the bridge blocks the exo face. OH ends exo, cis to the bridge (isoborneol, 90 %): steric approach control.
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Coverscamphor reductionLiAlH₄isoborneolsteric approach controlexo/endo attack
All parts of Question 5
- 5(a) Number of ¹H NMR signals in (A) and (B)10 marks
- 5(b) C=C stretch of methylenecyclopropane and methylenecyclobutane10 marks
- 5(c) Acetylene to neoprene; why rubber perishes in air10 marks
- 5(d) LiAlH₄ reduction of camphor: OH cis to the bridge10 marks
- 5(e) Photolysis of acetone: vapour phase and room temperature10 marks