UPSC Civil Services (Mains), Chemistry optional · 2024 · Paper II
Q2(c)(ii). 2-Methylpent-2-enoic acid by the Reformatsky reaction
Question
How is the following compound prepared using a Reformatsky reaction? CH₃CH₂CH=C(CH₃)–COOH
Model answer
The free solution for 2024 answers questions 1, 3, 5, 6 and 8, the ones picked in its time plan. Question 2 is answered in full in the Chemistry Paper II, 2021 to 2025 book, with every part of every paper.
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UPSC Civil Services (Main) Chemistry Paper II: Model Answers 2021 to 2025
- All eight questions of each paper, with the question printed above its answer
- Mechanisms drawn out and labelled on the scheme
- Topic-wise weightage and a topic-wise index
CoversReformatsky reactionorganozincβ-hydroxy esterα-bromo ester2-methylpent-2-enoic acid
All parts of Question 2
- 2(a)(i) kH/kD = 7.1 for 2-phenylethyl bromide with ethoxide10 marks
- 2(a)(ii) 1,2- and 1,4-addition of HBr to butadiene5 marks
- 2(b)(i) Benzaldehyde with diethyl malonate and pyridine10 marks
- 2(b)(ii) Structure of X; name; proof of syn-elimination5 marks
- 2(c)(i) Products of three reactions15 marks
- 2(c)(ii) 2-Methylpent-2-enoic acid by the Reformatsky reaction5 marks