Q1(c). Friedel–Crafts, Wittig, dihydroxylation and pinacol rearrangement
Identify the major products V, W, X, Y and Z in the following reaction sequences:
[structure] + [structure] → (AlCl₃, excess benzene) V
[structure] → ((i) PPh₃, (ii) BuLi) W → (V) X → (OsO₄ (cat.), NMO, ^tBuOH, H₂O) Y → (H₂SO₄) Z
Answer in brief
V = benzophenone; W = C₅H₈=PPh₃; X = (diphenylmethylidene)cyclopentane; Y = the 1,2-diol; Z = 2,2-diphenylcyclohexan-1-one, formed by a pinacol rearrangement with ring expansion.
Key points
- Introduction. The sequence links five standard steps: Friedel–Crafts acylation, ylide formation, Wittig olefination, syn-dihydroxylation and an acid-catalysed pinacol rearrangement, which here enlarges the five-membered ring.
- V. AlCl₃ forms the benzoyl (acylium) ion PhC#O⁺, which substitutes benzene: V = benzophenone, Ph₂C=O. The ketone complexes AlCl₃, so no second acylation occurs.
The full model answer
Written out in full, as it should go in the answer booklet. The solution page with its diagrams follows it.
Introduction. The sequence links five standard steps: Friedel–Crafts acylation, ylide formation, Wittig olefination, syn-dihydroxylation and an acid-catalysed pinacol rearrangement, which here enlarges the five-membered ring.
Scheme: V = benzophenone; W = cyclopentylidenetriphenylphosphorane; X = (diphenylmethylidene)cyclopentane
V. AlCl₃ forms the benzoyl (acylium) ion PhC#O⁺, which substitutes benzene: V = benzophenone, Ph₂C=O. The ketone complexes AlCl₃, so no second acylation occurs.
W. PPh₃ displaces chloride (SN2) to give cyclopentyltriphenylphosphonium chloride; BuLi removes the α-H: W = the ylide C₅H₈=PPh₃, cyclopentylidenetriphenylphosphorane.
X. The ylide adds to the C=O of V to form an oxaphosphetane, which collapses to Ph₃P=O and the alkene: X = (diphenylmethylidene)cyclopentane, C₅H₈=CPh₂.
Y. OsO₄/NMO (Upjohn conditions) adds two OH groups syn through a cyclic osmate ester; NMO reoxidises osmium, so only a catalytic amount is needed: Y = 1-[hydroxy(diphenyl)methyl]cyclopentan-1-ol, a pinacol (1,2-diol).
Z. Acid protonates the OH that leaves the more stable cation, the one on the diphenyl carbon (tertiary and doubly benzylic). A ring C–C bond then migrates to this cation (1,2-alkyl shift, ring expansion, the step that relieves strain), and the oxocarbenium ion loses H⁺.
Scheme: The ring bond migrates to the cation: the five-membered ring becomes a cyclohexanone.
Conclusion. V = benzophenone; W = C₅H₈=PPh₃; X = (diphenylmethylidene)cyclopentane; Y = the 1,2-diol; Z = 2,2-diphenylcyclohexan-1-one, formed by a pinacol rearrangement with ring expansion.
Application. Pinacol ring expansion of cyclic 1,2-diols is a laboratory route to spiro and cyclohexanone frameworks; the Wittig reaction is used industrially in the synthesis of vitamin A.
Practising this answer? Write it in a Mains test and get it checked by VKC. Civil Services Mains test series · Telegram

All parts of Question 1
- 1(a) [10]Annulene isomers; sydnone and tropolone10 marks
- 1(b) Solvolysis of anti- and syn-7-norbornenyl tosylates10 marks
- 1(c) Friedel–Crafts, Wittig, dihydroxylation and pinacol rearrangement10 marks
- 1(d) HCl on 1-phenylpropyne: E/Z, kinetic and thermodynamic products10 marks
- 1(e) Diels–Alder of o-xylylene; photochemistry of butadiene10 marks