Q6(c). Iron–hydrogen cell
Write oxidation half reaction and reduction half reaction and calculate EMF of the following cell at 298 K: Fe(s)/Fe²⁺(aq)(0.001 M)//H+(aq)(1 M)/H₂(g)(1 atm),Pt. Standard reduction potentials of Fe²⁺/Fe = -0.44 V and H+/1/2H₂ = 0.0 V.
Answer in brief
The cell EMF is approximately 0.529 V under the stated concentration approximation.
Part of VKC Basic
Read the key points and the full model answer with VKC Basic
VKC Basic (₹999 for 6 months) opens every solved answer, the notes, the handbook and the daily answer archive. Every Mains test series includes it.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.
CoversIron–hydrogen cellNernst equation
All parts of Question 6
- 6(a) Phosphorus disproportionation10 marks
- 6(b) Redox classification10 marks
- 6(c) Iron–hydrogen cell10 marks