UPSC Combined Geo-Scientist, Mains · 2021 · Mains Paper I
Q1(b). Fifth ammonia ligand on copper(II)
Question
The stepwise formation constants for the complexes of NH₃ with [Cu(OH₂)₆]²⁺(aq) are log Kf1 = 4.15, log Kf2 = 3.50, log Kf3 = 2.89, log Kf4 = 2.13, and log Kf5 = −0.52. Why is Kf5 so different?
Answer in brief
The fifth NH₃ must occupy a weak, elongated axial site of Jahn-Teller-distorted Cu(II); K₅ ≈ 0.302 is consequently much smaller than K₄ ≈ 135.
Key points
- Cu²⁺ is d⁹, with uneven occupation of the octahedral eg set. Axial elongation stabilises the complex.
- The first four NH₃ ligands favour the four short equatorial positions, giving [Cu(NH₃)₄(H₂O)₂]²⁺ with long axial Cu-OH₂ bonds.
- The fifth NH₃ replaces water at a long, weak axial position; its binding gains much less energy than equatorial binding.
- K₄ = 102.13 = 134.9; K₅ = 10−0.52 = 0.302; K₄/K₅ ≈ 447. Ordinary statistical decreases alone do not explain this abrupt fall.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.

Topic notes: crystal field theory, with every Civil Services, IFoS and Geo-Scientist PYQ →
Coversstepwise formation constantJahn-Teller effectcopper ammine complexCu(II) d9axial elongation
All parts of Question 1
- 1(a) Quartz-type aluminophosphate5 marks
- 1(b) Fifth ammonia ligand on copper(II)5 marks
- 1(c) Why hydride and phosphine are strong-field ligands5 marks
- 1(d) Indicator choice for weak-acid titration5 marks
- 1(e) Postprecipitation versus coprecipitation5 marks
- 1(f) Role of mercuric chloride in iron titration5 marks
- 1(g) Chelators in complexometric titrations5 marks
- 1(h) Carbonyl C-O bond strengths5 marks
- 1(i) Balancing nuclear reactions5 marks
- 1(j) Orbital contribution to magnetic moments5 marks