Q4(a). VBT for tetrahedral nickel complexes
How does the VBT account for the following facts? (i) [NiCl₄]²⁻ is paramagnetic and tetrahedral. (ii) [Ni(CO)₄] is diamagnetic and tetrahedral.
Answer in brief
Both use four sp³ acceptor hybrids in the traditional VBT picture. Ni(II)-chloride has two unpaired 3d electrons; Ni(0)-carbonyl has a paired 3d¹⁰ configuration.
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Coversvalence bond theorysp3 hybridisation[NiCl4]2- paramagneticNi(CO)4 diamagnetictetrahedral complexes
All parts of Question 4
- 4(a) VBT for tetrahedral nickel complexes10 marks
- 4(b) Selection rules and absorption intensity10 marks
- 4(c) Square-planar tetracyanonickelate(II)10 marks