Q3(b). Salt hydrolysis; sodium acetate, 0.01 M
What is meant by salt hydrolysis? Calculate (i) the hydrolysis constant, (ii) the degree of hydrolysis in %, and (iii) the pH of a 0.01 molar solution of sodium acetate at 25 °C. [Given: Ka for acetic acid = 1.8 × 10⁻⁵ and ionic product of water at 25 °C = 1.1 × 10⁻¹⁴]
Answer in brief
(i) Kh = 6.11 × 10⁻¹⁰, (ii) h = 0.0247%, (iii) pH = 8.35.
Part of VKC Basic
Read the key points and the full model answer with VKC Basic
VKC Basic (₹999 for 6 months) opens every solved answer, the notes, the handbook and the daily answer archive. Every Mains test series includes it.
The full model answer
As written for the answer booklet: the diagram carries the working, the lines stay short. Read here only; it is not offered as a download.
Coverssalt hydrolysishydrolysis constantdegree of hydrolysissodium acetate pHKh = Kw/Ka
All parts of Question 3
- 3(a) pH at the equivalence points of H₃PO₄ with KOH15 marks
- 3(b) Salt hydrolysis; sodium acetate, 0.01 M15 marks