Q1(c). Phosphate buffer at pH 7.40
Phosphate ions are abundant in cells. The typical total phosphate concentration [HPO₄²⁻]+[H₂PO₄⁻] is 2.0×10⁻² M. What are the concentrations of HPO₄²⁻ and H₂PO₄⁻ at pH 7.40? (Given: pKₐ for H₂PO₄⁻ ion is 7.20.)
Answer in brief
[HPO₄²⁻]=1.23×10⁻² M and [H₂PO₄⁻]=7.7×10⁻³ M.
Key points
- the cell works as a buffer because pH 7.40 is within one unit of pKₐ 7.20; the buffer capacity peaks at pH = pKₐ.
The full model answer
Worked out step by step, as it should go in the answer booklet. The solution sheet follows it.
H₂PO₄⁻ + H₂O ⇌ H₃O⁺ + HPO₄²⁻
pH=pKₐ+log([HPO₄²⁻])/([H₂PO₄⁻]) ⇒ log([HPO₄²⁻])/([H₂PO₄⁻])=7.40-7.20=0.20 ⇒ ratio=10^(0.20)=1.585
With [HPO₄²⁻]+[H₂PO₄⁻]=2.0×10⁻² M:
[H₂PO₄⁻]=(0.020)/(1+1.585)=7.74×10⁻³ M, [HPO₄²⁻]=0.020-0.00774=1.23×10⁻² M
the cell works as a buffer because pH 7.40 is within one unit of pKₐ 7.20; the buffer capacity peaks at pH = pKₐ.

CoversbufferPhosphate buffer at pH 7.40
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