Q5(b). Fe(III) left after three extractions with ether
Calculate the weight of Fe(III) left unextracted from a 100 mL aqueous solution having 500 mg of Fe³⁺ ion in 6 N HCl after three extractions with 10 mL of diethyl ether in each go. [Given: The distribution ratio between water and diethyl ether is 150]
Answer in brief
Each extraction leaves 1/16 of the iron in the water; after three extractions 500 × (1/16)³ = 0.122 mg of Fe(III) is left and 99.98 % has been extracted.
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Coverssolvent extractiondistribution ratiomultiple extractioniron ether extractionfraction unextracted
All parts of Question 5
- 5(a) New method against a reference method: F-test and t-test15 marks
- 5(b) Fe(III) left after three extractions with ether10 marks
- 5(c) Double-beam flame atomic absorption spectrophotometer5 marks