Q7(d). Phenyl acetate to A, B, C, D: Reimer–Tiemann and Wittig reactions
Complete the following reaction and sketch a suitable mechanism for conversion of A → B and B → C: [phenyl acetate → (H₃O⁺) A → (CHCl₃, KOH) B → (Ph₃P⁺–CH₂⁻) C → (HBr, peroxide) D; structures given in the paper]
Answer in brief
A = phenol; B = salicylaldehyde (Reimer–Tiemann); C = 2-vinylphenol (Wittig); D = 2-(2-bromoethyl)phenol (anti-Markovnikov HBr addition).
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CoversReimer–Tiemann reactiondichlorocarbeneWittig reactionsalicylaldehydeanti-Markovnikov additionperoxide effect
All parts of Question 7
- 7(a) Acetylene on a Ziegler–Natta catalyst: polyacetylene10 marks
- 7(b) Ketone with diethyl carbonate: crossed Claisen condensation5 marks
- 7(c) Lactic acid from ethanal through the cyanohydrin5 marks
- 7(d) Phenyl acetate to A, B, C, D: Reimer–Tiemann and Wittig reactions10 marks