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UPSC Combined Geo-Scientist

Chemist

  • 3 descriptive papers
  • 200 marks each
  • 3 h per paper

Mains Paper III covers analytical and organic chemistry.

UPSC Combined Geo-Scientist, Mains · 2026 · Mains Paper III

Q4(a). Ion-exchange capacity of an anion-exchange resin

  • 10 marks
  • Topic: Chromatography
  • Answered
Question

Describe how the ion-exchange capacity of an anion-exchange resin can be measured using standard NaOH, standard HCl or any other reagent.

Answer in brief

Convert the resin completely to the OH⁻ form, shake a weighed amount with an excess of standard HCl, and back-titrate the unused HCl with standard NaOH. Capacity (meq g⁻¹) =V_(HCl)M_(HCl)-V_(NaOH)M_(NaOH)m.

Key points

  • wash the strong-base resin (R–N⁺Cl⁻) in a column with 1 M NaOH until the effluent has no Cl⁻ (AgNO₃ test), then with distilled CO₂-free water until neutral (pH 7). Dry at 105°C and weigh 1.000 g (or work with the drained resin…
  • add 50.0 mL of 0.1000 M HCl (excess) in a stoppered flask and shake or stir for 24 h so that every OH⁻ site is replaced by Cl⁻.
  • filter; titrate an aliquot (e.g. 10.0 mL) of the filtrate with 0.1000 M NaOH, methyl red or phenolphthalein indicator.
  • 10.0 mL of filtrate needs 4.20 mL of NaOH, so unused HCl =5×4.20×0.1000=2.10 mmol; used =5.00-2.10=2.90 mmol; capacity =2.90 meq per 1.000 g =2.9 meq g⁻¹.

The full model answer

Worked out step by step, as it should go in the answer booklet. The solution sheet follows it.

R-N+(CH₃)₃ OH⁻ + HCl → R-N+(CH₃)₃ Cl⁻ + H₂O

  1. Conditioning: wash the strong-base resin (R–N⁺Cl⁻) in a column with 1 M NaOH until the effluent has no Cl⁻ (AgNO₃ test), then with distilled CO₂-free water until neutral (pH 7). Dry at 105°C and weigh 1.000 g (or work with the drained resin and find its dry mass).
  2. Exchange: add 50.0 mL of 0.1000 M HCl (excess) in a stoppered flask and shake or stir for 24 h so that every OH⁻ site is replaced by Cl⁻.
  3. Titration: filter; titrate an aliquot (e.g. 10.0 mL) of the filtrate with 0.1000 M NaOH, methyl red or phenolphthalein indicator.
  4. Calculation (specimen figures): 10.0 mL of filtrate needs 4.20 mL of NaOH, so unused HCl =5×4.20×0.1000=2.10 mmol; used =5.00-2.10=2.90 mmol; capacity =2.90 meq per 1.000 g =2.9 meq g⁻¹.
  5. Alternative (column method): load the resin in the Cl⁻ form, elute all Cl⁻ with 1 M NaNO₃ (or Na₂SO₄), titrate the Cl⁻ in the eluate with AgNO₃ (Mohr). Capacity =n(Cl⁻)/m.

typical capacity: polystyrene–DVB strong-base resin 3–4 meq g⁻¹ (dry); the capacity fixes how much sample can be loaded on a column before breakthrough.

Model answer to Q4(a), 2026 Mains Paper III: solution page 11
Solution page 11 of 30

Coversion-exchange capacityIon-exchange capacity of an anion-exchange resin

All parts of Question 4