QuestionCoordination / unpaired electrons
Consider the following complexes:
- [Fe(H₂O)₆]²⁺
- [Fe(CN)₆]³⁻
- [Fe(CN)₆]⁴⁻
- [Fe(H₂O)₆]³⁺
Which one of the following is the correct order of number of unpaired electrons in the above complexes?
- (a) 4 > 1 > 2 > 3
- (b) 1 > 2 > 3 > 4
- (c) 3 > 2 > 1 > 4
- (d) 4 > 2 > 1 > 3
Answer: (a) 4 > 1 > 2 > 3
4. [Fe(H₂O)₆]³⁺ d⁵ high spin → 5. 1. [Fe(H₂O)₆]²⁺ d⁶ high spin → 4. 2. [Fe(CN)₆]³⁻ d⁵ low spin → 1. 3. [Fe(CN)₆]⁴⁻ d⁶ low spin → 0. Order 4 > 1 > 2 > 3 → (a).