Questions-block / hydroxides
Consider the following hydroxides:
- Be(OH)₂
- Sr(OH)₂
- Mg(OH)₂
- Ba(OH)₂
The correct order of basicity of the above hydroxides will be:
- (a) Sr(OH)₂ < Be(OH)₂ < Ba(OH)₂ < Mg(OH)₂
- (b) Be(OH)₂ < Mg(OH)₂ < Ba(OH)₂ < Sr(OH)₂
- (c) Mg(OH)₂ < Ba(OH)₂ < Sr(OH)₂ < Be(OH)₂
- (d) Be(OH)₂ < Mg(OH)₂ < Sr(OH)₂ < Ba(OH)₂
Answer: (d) Be(OH)₂ < Mg(OH)₂ < Sr(OH)₂ < Ba(OH)₂
Down group 2, ionisation energy falls and M–OH bond becomes more ionic → basicity rises: Be(OH)₂ (amphoteric) < Mg(OH)₂ < Sr(OH)₂ < Ba(OH)₂ → (d). Solubility also rises down the group.