QuestionIonic equilibrium / pH
What will be the value of pOH of 0.03M aqueous solution of HCl at 25°C? (Given log 0.03 = –1.52)
- (a) 12.21
- (b) 12.48
- (c) 11.48
- (d) 10.48
Answer: (b) 12.48
Strong acid: [H⁺] = 0.03 M. pH = −log 0.03 = 1.52. pOH = 14 − 1.52 = 12.48 → (b).