QuestionRedox / equivalent weight
Equivalent weight of K₂Cr₂O₇ in acidic medium will be: (Atomic weight of K = 39, Cr = 52 and O = 16)
- (a) 294 / 2
- (b) 294/ 3
- (c) 294/ 6
- (d) 294
Answer: (c) 294/ 6
Acidic: Cr₂O₇²⁻ + 14H⁺ + 6e⁻ → 2Cr³⁺ + 7H₂O (Cr +6 → +3, two Cr). n-factor = 6. Eq. wt = M/6 = 294/6 = 49 → (c).