QuestionGaseous state / Graham's law
50 mL of H₂ gas diffuses through a small hole from a vessel in 20 minutes. Time taken by 40 mL of O₂ gas to diffuse under similar condition will be:
- (a) 12 minutes
- (b) 64 minutes
- (c) 8 minutes
- (d) 32 minutes
Answer: (b) 64 minutes
Rate ∝ 1/√M. r(H₂) = 50/20 = 2.5 mL/min. r(O₂) = 2.5 × √(2/32) = 0.625 mL/min. Time for 40 mL = 40/0.625 = 64 min → (b).