The latent heat of vaporization of Br₂ at 59˚C and at 1 atm pressure is 29.2 kJ mol⁻¹. The value of ∆U would be: (R = 8.314 × 10⁻³ kJ mol⁻¹ K⁻¹)

Question

Vimal Swarnkar · Accepted Answer

(a) 26.44 kJ mol⁻¹. Br₂(l) → Br₂(g), Δn(g) = 1, T = 332 K. ΔU = ΔH − ΔnRT = 29.2 − 8.314 × 10⁻³ × 332 = 29.2 − 2.76 = 26.44 kJ mol⁻¹ → (a).

Answer

(b) 2.644 kJ mol⁻¹

Answer

(c) 264.4 kJ mol⁻¹

Answer

(d) 31.96 kJ mol⁻¹

Geo-Scientist Prelims 2020 Chemistry Q50: The latent heat of vaporization of Br₂ at 59˚C and at 1 atm…